奇偶位交换

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/*用0xAAAAAAAA与x相与求的奇数位上数字(偶数位上数字为0) 用0x 55555555 与x相与求的偶数位上数字(奇数位上数字为0) oddVal右移一位 even左移一位相加即可。*/ class Exchange { public:     int exchangeOddEven(int x) {         // write code here         int oddVal = (x & 0xAAAAAAAA); // bit 1 3 5 ... 31         int evenVal = (x & 0x55555555); // bit 0 2 4 ... 30         return (oddVal >> 1) + (evenVal << 1);     } };