ACM模板——康托展开

 1 #include<iostream>
 2 #include<cstdio>
 3 #include<cstring>
 4 #define _for(i,a,b) for(int i = (a);i < b;i ++)
 5 typedef long long ll;
 6 using namespace std;
 7 ll a[10003];
 8 ll rnt[10003];
 9 int vis[10003];
10 int m,n;
11 inline ll read()
12 {
13     ll ans = 0;
14     char ch = getchar(), last = ' ';
15     while(!isdigit(ch)) last = ch, ch = getchar();
16     while(isdigit(ch)) ans = (ans << 1) + (ans << 3) + ch - '0', ch = getchar();
17     if(last == '-') ans = -ans;
18     return ans;
19 }
20 inline void write(ll x)
21 {
22     if(x < 0) x = -x, putchar('-');
23     if(x >= 10) write(x / 10);
24     putchar(x % 10 + '0');
25 }
26 int main()
27 {
28     n = read(),m = read();
29     ll res = 0;
30     _for(i,0,n)
31         a[i] = read();
32     
33     _for(i,0,n)
34     {
35         ll tsum = 0;
36         _for(j,0,i+1)
37             if(a[j] <= a[i])
38                 tsum ++;
39         rnt[i] = a[i]-tsum;
40     }
41     rnt[n-1] += m;
42     for(int i = n-1;i > 0;i--)
43     {
44         rnt[i-1] += rnt[i]/(n-i);
45         rnt[i] %= n-i;
46     }
47     
48     memset(vis,0,sizeof(vis));
49     _for(i,0,n)
50     {
51         rnt[i] ++;
52         int j;
53         for(j = 1;j <= n;j ++)
54         {
55             if(vis[j])
56                 continue;
57             rnt[i] --;
58             if(!rnt[i])    
59                 break;
60         }
61         vis[j] = 1;
62         printf("%d ",j);
63     }
64     return 0;
65 }

洛谷 P1088 火星人,代码包括康托展开,变进制数进位合法调整,康托展开逆运算

posted @ 2019-07-30 12:56  Asurudo  阅读(235)  评论(0编辑  收藏  举报