Leetcode-5040 Coloring A Border(边框着色)
1 const int dx[] = {1,-1,0,0}; 2 const int dy[] = {0,0,1,-1}; 3 #define _for(i,a,b) for(int i = (a);i < (b);i ++) 4 class Solution 5 { 6 public: 7 int vis[60][60]; 8 void go(vector<vector<int>>& grid, int r0, int c0, int color,int lo) 9 { 10 vis[r0][c0] = 1; 11 grid[r0][c0] = -color; 12 _for(i,0,4) 13 { 14 int nx = r0 + dx[i]; 15 int ny = c0 + dy[i]; 16 if(nx>=0 && nx<grid.size() && ny>=0 && ny<grid[0].size() 17 && vis[nx][ny]==0 && grid[nx][ny]==lo) 18 { 19 go(grid,nx,ny,color,lo); 20 } 21 } 22 } 23 vector<vector<int>> colorBorder(vector<vector<int>>& grid, int r0, int c0, int color) 24 { 25 memset(vis,0,sizeof(vis)); 26 int lo = grid[r0][c0]; 27 go(grid,r0,c0,color,lo); 28 vector<pair<int,int>> vv; 29 _for(i,0,grid.size()) 30 _for(j,0,grid[i].size()) 31 if(grid[i][j]<0) 32 { 33 if(i==0 || i==grid.size()-1 || j==0 || j==grid[i].size()-1) 34 continue; 35 if(grid[i+1][j]==-color && grid[i-1][j]==-color && grid[i][j+1]==-color && grid[i][j-1]==-color) 36 vv.push_back({i,j}); 37 // grid[i][j] = lo; 38 } 39 _for(i,0,vv.size()) 40 grid[vv[i].first][vv[i].second] = lo; 41 _for(i,0,grid.size()) 42 _for(j,0,grid[i].size()) 43 { 44 if(grid[i][j]<0) 45 grid[i][j] = -grid[i][j]; 46 } 47 48 return grid; 49 } 50 };