1 #define _for(i,a,b) for(int i = (a);i < (b);i ++)
2 class Solution
3 {
4 public:
5 int findNumberOfLIS(vector<int>& nums)
6 {
7 int sz = nums.size();
8 vector<pair<int,int>> dp (sz,{1,1});//LISlen times
9
10 int LISlen = 1;
11 for(int i = 1;i < sz;i ++)
12 {
13 for(int j = 0;j < i;j ++)
14 {
15 if(nums[i]>nums[j]&&dp[j].first+1>dp[i].first)
16 {
17
18 dp[i].first = dp[j].first+1;
19 dp[i].second = dp[j].second;
20 LISlen = max(LISlen,dp[i].first);
21 }
22 else if(nums[i]>nums[j]&&dp[j].first+1==dp[i].first)
23 {
24 dp[i].second += dp[j].second;
25 }
26 }
27 }
28
29 int rnt = 0;
30 _for(i,0,sz)
31 if(dp[i].first==LISlen)
32 rnt += dp[i].second;
33 return rnt;
34 }
35 };
