python列表及循环语句综合练习——简单模拟购物车 

 1 # -*- coding: utf-8 -*-
 2 
 3 '''
 4 ------------------------------------------------
 5 假设：加入购物车即扣款
 6 问题描述：非int型输入值输入，无法使代码不报错，输出至报错
 7 解决方案：isdigit()判断输入合法性
 8 状态：已解决
 9 ------------------------------------------------
10 '''
11 
12 salary = input("请输入你的工资：")
13 if salary.isdigit():
14     commodity_msg_list = ['none', '1.  iphone6s       ￥5800', '2.  mac book       ￥9000', '3.  coffee         ￥32', '4.  python book    ￥80', '5.  bicycle         ￥1500']
15     commodity_price = [0, 5800, 9000, 32, 80, 1500]
16     commodity_bought = []
17     buy_times = 1
18     while buy_times > 0:
19         commodity_msg = '''
20                     欢迎来到本店！
21     
22         本店有如下商品：
23                 1.  iphone6s       ￥5800
24                 2.  mac book       ￥9000
25                 3.  coffee         ￥32
26                 4.  python book    ￥80
27                 5.  bicyle         ￥1500 '''
28         print(commodity_msg)
29         bianhao = [0, 1, 2, 3, 4, 5]
30         commodity_bianhao = input("请输入您想购买的商品编号：\n")
31         if commodity_bianhao.isdigit():
32             if int(commodity_bianhao) in bianhao:
33                 if commodity_price[bianhao[int(commodity_bianhao)]] > int(salary):
34                     chajia = int(salary) - commodity_price[bianhao[int(commodity_bianhao)]]
35                     print("余额不足，差￥%d!" % chajia)
36                     buy_times += 1
37                 else:
38                     chajia = int(salary) - commodity_price[bianhao[int(commodity_bianhao)]]
39                     print("已加入购物车，您的余额为：\n￥%d" % chajia)
40                     commodity_bought.append(str(commodity_msg_list[bianhao[int(commodity_bianhao)]]))
41                     print("您的购物车中已有以下商品：")
42                     print(str(commodity_bought))
43                     salary = int(chajia)
44                     buy_times += 1
45             else:
46                 print("对不起，输入错误，没有您需要的商品，请重新输入!")
47                 buy_times += 1
48         else:
49             print("invalid input!")
50             buy_times += 1
51         end_buy = input("退出购买请输入q,继续购买请输入c:\n")
52         if end_buy == "q":
53             if len(commodity_bought) == 0:
54                 cq = input('''您尚未购买任何商品！\n输入c再看看 or 输入q结束:''')
55                 if cq == "q":
56                     print("谢谢您的光临，欢迎下次再来！")
57                     break
58                 else:
59                     buy_times += 1
60             else:
61                 print("谢谢您的光临，欢迎下次再来！")
62                 break
63         buy_times += 1
64 else:
65     print("invalid input!")

 

posted @ 2018-02-04 17:32  静静等待繁华落尽  阅读(342)  评论(0)  编辑  收藏  举报