获取Http请求参数

客户端表单项:

<form action="Default" method="post" >
    用户名:<input type="text" name="userName" />
    <input type="submit" value="提交" />
</form>
您输入的用户名是:@ViewBag.userName

控制器中接收:

public class TestController : Controller
{
    [HttpGet]
    public ActionResult Default()
    {
        return View();
    }

    [HttpPost]
    public ActionResult Default(string abc)
    {
        ViewBag.userName = Request["userName"];
     或
     ViewBag.userName = HttpContext.Request["userName"];
     或
     ViewBag.userName = System.Web.HttpContext.Current.Request["userName"];
return View(); } }

普通类中接收:

public class RequestContent
{
    public string GetRequestValue(HttpRequestBase request)
    {
        return request["userName"];
    }

    public string GetRequestValue(HttpContextBase context)
    {
        return context.Request["userName"];
    }

    public string GetRequestValue()
    {
        return System.Web.HttpContext.Current.Request["userName"];
    }
}

控制器中可以这样调用他们:

public class TestController : Controller
{
    //
    // GET: /Test/
    [HttpGet]
    public ActionResult Default()
    {
        return View();
    }

    [HttpPost]
    public ActionResult Default(string abc)
    {
        RequestContent request = new RequestContent();

        ViewBag.userName = request.GetRequestValue(Request);
        或
        ViewBag.userName = request.GetRequestValue(HttpContext);
        或
        ViewBag.userName = request.GetRequestValue();
           
        return View(); 
    }
}
posted @ 2017-09-09 14:43  Arlar  阅读(3512)  评论(0编辑  收藏  举报