HDU 5387 Clock

题意：给一个时间，求三个时针之间的夹角，分数表示。

 

解法：算算算。统一了一下分母。

 

代码：

#include<stdio.h>
#include<iostream>
#include<algorithm>
#include<string>
#include<string.h>
#include<math.h>
#include<limits.h>
#include<time.h>
#include<stdlib.h>
#include<map>
#include<queue>
#include<set>
#include<stack>
#include<vector>
#define LL long long
using namespace std;
int main()
{
    int T;
    while(~scanf("%d", &T))
    {
        while(T--)
        {
            int hh, mm, ss;
            scanf("%d:%d:%d", &hh, &mm, &ss);
            int hs = hh * 3600 + mm * 60 + ss;
            int ms = mm * 60 + ss;
            ms *= 12;
            ss *= 120 * 6;
            hs %= 43200;
            ms %= 43200;
            ss %= 43200;
            int hhmm = abs(hs - ms);
            if(hhmm > 120 * 180)
                hhmm = 120 * 360 - hhmm;
            int hhss = abs(hs - ss);
            if(hhss > 120 * 180)
                hhss = 120 * 360 - hhss;
            int mmss = abs(ms - ss);
            if(mmss > 120 * 180)
                mmss = 120 * 360 - mmss;
            int r = __gcd(hhmm, 120);
            if(r == 120 || hhmm == 0)
                printf("%d", hhmm / 120);
            else
                printf("%d/%d", hhmm / r, 120 / r);
            r = __gcd(hhss, 120);
            if(r == 120 || hhss == 0)
                printf(" %d", hhss / 120);
            else
                printf(" %d/%d", hhss / r, 120 / r);
            r = __gcd(mmss, 120);
            if(r == 120 || mmss == 0)
                printf(" %d ", mmss / 120);
            else
                printf(" %d/%d ", mmss / r, 120 / r);
            puts("");
        }
    }
    return 0;
}