用线程来实现图标的闪跳

new Thread() {
			public void run() {
				while (true) {
					rightHelpHandFlag = !rightHelpHandFlag;
					try {
						Thread.sleep(600);//600
					} catch (Exception e) {
						// TODO: handle exception
					}
				}
			};
		}.start();



核心代码是:rightHelpHandFlag = !rightHelpHandFlag;

posted @ 2015-06-12 09:38  Anzhongliu  阅读(174)  评论(0编辑  收藏  举报