Problem Description

Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?

Input

The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.

Output

One integer per line representing the maximum of the total value (this number will be less than 231).

Sample Input

1
5 10
1 2 3 4 5
5 4 3 2 1

Sample Output

14

Author

Teddy

Source

HDU 1st “Vegetable-Birds Cup” Programming Open Contest
 
 
思路：01背包裸题。01背包：有限的背包容量取最大的价值，每样东西选择取或不取
 
 1 #include <iostream>
 2 #include<cstdio>
 3 #include<algorithm>
 4 #include<cstring>
 5 #include<cmath>
 6 using namespace std;
 7 
 8 long long va[1005];
 9 int vo[1005];
10 long long dp[1005];
11 
12 int main()
13 {
14     int T,n,v,i,j;
15     scanf("%d",&T);
16     while(T--)
17     {
18         scanf("%d%d",&n,&v);
19         for(i=1;i<=n;i++)
20             scanf("%lld",&va[i]);
21         for(i=1;i<=n;i++)
22             scanf("%d",&vo[i]);
23         memset(dp,0,sizeof(dp));
24         for(i=1;i<=n;i++)
25         {
26             for(j=v;j>=vo[i];j--)
27             {
28                 dp[j]=max(dp[j],dp[j-vo[i]]+va[i]);
29             }
30         }
31         printf("%lld\n",dp[v]);
32     }
33     return 0;
34 }