HDU-1575-Tr A(矩阵快速幂)

  • 矩阵快速幂
    #include"bits/stdc++.h"
    using namespace std;
    const int mod = 9973;
    int n, k;
    struct Mat {
        int mat[11][11];
        Mat() {
            memset(mat, 0, sizeof(mat));
        }
        friend Mat operator * (Mat a, Mat b) {
            Mat c;
            for(int i = 1; i <= n; i++)
            for(int j = 1; j <= n; j++)
            for(int k = 1; k <= n; k++)
            c.mat[i][j] = (c.mat[i][j] + a.mat[i][k] * b.mat[k][j]) % mod;
            return c;
        }
    };
    Mat Mat_pow(Mat m, int k) {
        Mat ans;
        for(int i = 1; i <= n; i++)
        ans.mat[i][i] = 1;
        while(k) {
            if(k & 1)
            ans = ans * m;
            m = m * m;
            k >>= 1;
        }
        return ans;
    }
    int main() {
        int T; Mat m;
        scanf("%d", &T);
        while(T--) {
            scanf("%d%d", &n, &k);
            for(int i = 1; i <= n; i++)
            for(int j = 1; j <= n; j++)
            scanf("%d", &m.mat[i][j]);
            m = Mat_pow(m, k);
            int ans = 0;
            for(int i = 1; i <= n; i++)
            ans += m.mat[i][i];
            printf("%d\n", ans % mod);
        }
        return 0;
    }

     

posted @ 2018-11-03 17:08  Jathon-cnblogs  阅读(201)  评论(0编辑  收藏  举报