Python FIFO算法模拟

#!/usr/bin/python
 
array = (7, 0, 1, 2, 0, 3, 0, 4, 2, 3, 0, 3, 2, 1, 2, 0, 1, 7, 0, 1)
memory = []
pointer = 0
 
# if the memory is empty
 
 
def is_empty(_list_):
     if len(_list_) == 0:
         re1 = 1
     else:
         re1 = 0
     return re1
 
 
# if the memory is empty
 
def is_fulled(_list_):
     if len(_list_) == 3:
         re1 = 1
     else:
         re1 = 0
     return re1
 
 
def search(target, _list_):
    exist = 0
    for each_item in _list_:
        if each_item == target:
            exist = 1
            break
    return exist
 
# put in memory
 
 
def push(target, _list_, temp):
    if is_empty(_list_) == 1 or is_fulled(_list_) == 0:
        _list_.append(target)
    else:
        if search(target, _list_) == 1:
            print('no exchange')
        else:
            if temp > 2:
                temp = 0
                _list_.pop(temp)
                _list_.insert(temp, target)
                temp = temp + 1
            else:
                _list_.pop(temp)
                _list_.insert(temp, target)
                temp = temp + 1
    return temp
 
 
for each_item in array:
    pointer = push(each_item, memory, pointer)
    print(memory)

结果：结果：
[7]
[7, 0]
[7, 0, 1]
[2, 0, 1]
no exchange
[2, 0, 1]
[2, 3, 1]
[2, 3, 0]
[4, 3, 0]
[4, 2, 0]
[4, 2, 3]
[0, 2, 3]
no exchange
[0, 2, 3]
no exchange
[0, 2, 3]
[0, 1, 3]
[0, 1, 2]
no exchange
[0, 1, 2]
no exchange
[0, 1, 2]
[7, 1, 2]
[7, 0, 2]
[7, 0, 1]