伪代码

https://blog.csdn.net/weixin_43886797/article/details/85569998

white num1

white num2

|num（1）-num （2）|=num （3）

until |num （n-1）-num（n）|=|num（n）-num（n+1）|=constant

white the answer is the constant

e.g132,12

132-12=120

120-12=118

118-12=106

 

 

 

12-12=0

12-0=12

12-0=12

the answer is 12