UVA 488 - Triangle Wave

In this problem you are to generate a triangular wave form according to a specified pair of Amplitude and Frequency.

Input and Output

The input begins with a single positive integer on a line by itself indicating the number of the cases following, each of them as described below. This line is followed by a blank line, and there is also a blank line between two consecutive inputs.

Each input set will contain two integers, each on a separate line. The first integer is the Amplitude; the second integer is the Frequency.

For each test case, the output must follow the description below. The outputs of two consecutive cases will be separated by a blank line.

For the output of your program, you will be printing wave forms each separated by a blank line. The total number of wave forms equals the Frequency, and the horizontal ``height'' of each wave equals the Amplitude. The Amplitude will never be greater than nine.

The waveform itself should be filled with integers on each line which indicate the ``height'' of that line.

NOTE: There is a blank line after each separate waveform, excluding the last one.

Sample Input

1

3
2

Sample Output

1
22
333
22
1

1
22
333
22
1



#define RUN
#ifdef RUN

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <assert.h>
#include <string>
#include <iostream>
#include <sstream>
#include <map>
#include <set>
#include <vector>
#include <list>
#include <cctype> 
#include <algorithm>
#include <utility>
#include <math.h>

using namespace std;

#define MAXN 105

int n;
int amp, fre;



void printout(bool islast){

	for(int k=0; k<fre; k++){
		for(int i=1; i<=amp; i++){
			for(int j=1; j<=i; j++){
				printf("%d", i);
			}
			printf("\n");
		}
		for(int i=amp-1; i>=1; i--){
			for(int j=1; j<=i; j++){
				printf("%d", i);
			}
			printf("\n");
		}

		if(!islast){
			printf("\n");
		}
		else{
			if(k!=fre-1){
				printf("\n");
			}
		}
	}
}

int main(){

#ifndef ONLINE_JUDGE
	freopen("488.in", "r", stdin);
	freopen("488.out", "w", stdout); 
#endif

	scanf("%d", &n);

	for(int i=0; i<n; i++){
		getchar();
		getchar();

		scanf("%d%d", &, &fre);

		if(i != n-1){
			printout(false);
		}
		else{
			printout(true);
		}
		
	}



}


#endif


posted @ 2013-02-27 20:56  WingWing111  阅读(127)  评论(0编辑  收藏  举报