The Dragon of Loowater

在这里插入图片描述

Code

/*
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 */
// Virtual_Judge —— Dragon of Loowater UVA - 11292.cpp created by VB_KoKing on 2019-07-19.
/* Procedural objectives:

 Variables required by the program:

 Procedural thinking:
1.Dragon和Warrior两个数组用于保存输入数据
2.将两个数组按照从小打到排序
3.排除不能砍掉当前需要砍掉的头的Warrior不需要雇佣
4.输出结果
 Functions required by the program:
 
 Determination algorithm:
 
 Determining data structure:
 

*/
/* My dear Max said:
"I like you,
So the first bunch of sunshine I saw in the morning is you,
The first gentle breeze that passed through my ear is you,
The first star I see is also you.
The world I see is all your shadow."

FIGHTING FOR OUR FUTURE!!!
*/
#include <cstdio>
#include <algorithm>

using namespace std;

const int maxn = 20000 + 7;
int Dragon[maxn], Warrior[maxn];

int main() {
    int n, m;

    while(scanf("%d%d", &n, &m) == 2 && n && m) {
        
        for (int i = 0; i < n; i++) scanf("%d", &Dragon[i]);
        for (int i = 0; i < m; i++) scanf("%d", &Warrior[i]);

        sort(Dragon, Dragon + n);
        sort(Warrior, Warrior + m);

        int cost = 0, index = 0;
        
        for (int i = 0; i < m; i++) {
            if (Warrior[i] >= Dragon[index]){
                cost += Warrior[i];
                if (++index == n) break;    //只有在能砍头的情况下才累加index
            }
        }

        if (index < n) printf("Loowater is doomed!\n");
        else printf("%d\n", cost);
    }

    return 0;
}
posted @ 2019-07-19 12:58  AlexKing007  阅读(98)  评论(0编辑  收藏  举报