【codeforces 747E】Comments
【题目链接】:http://codeforces.com/problemset/problem/747/E
【题意】
给你一个类似递归的结构;
让你把每一层的字符串按照层,一层层地输出出来;
并输出层数;
【题解】
递归里面,写:
当前层开始的位置,这一层里面有多少个字符串,以及层的深度;
每次搞到下一层最右的下标就好;
然后每找到一个字符就加入到这一层里面;
【Number Of WA】
0
【完整代码】
#include <bits/stdc++.h>
using namespace std;
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1
#define LL long long
#define rep1(i,a,b) for (int i = a;i <= b;i++)
#define rep2(i,a,b) for (int i = a;i >= b;i--)
#define mp make_pair
#define pb push_back
#define fi first
#define se second
#define ms(x,y) memset(x,y,sizeof x)
#define Open() freopen("F:\\rush.txt","r",stdin)
#define Close() ios::sync_with_stdio(0),cin.tie(0)
typedef pair<int, int> pii;
typedef pair<LL, LL> pll;
const int dx[9] = { 0,1,-1,0,0,-1,-1,1,1 };
const int dy[9] = { 0,0,0,-1,1,-1,1,-1,1 };
const double pi = acos(-1.0);
const int N = 1e6 + 100;
string temp;
char s[N];
int len, ma;
vector <string> ans[N];
void dfs(int i, int should, int dep)
{
int j = i, num = 0;
while (1)
{
if (j>len) return;
temp = "";
while (j <= len && s[j] != ',')
{
temp += s[j];
j++;
}
ans[dep].pb(temp);
LL temp1 = 0;
j++;
while (j <= len && s[j] != ',')
{
temp1 = temp1 * 10 + s[j] - '0';
j++;
}
ma = max(ma, j + 1);
if (temp1 == 0)
{
j++;
}
else
{
ma = j + 1;
dfs(j + 1, temp1, dep + 1);
j = ma;
}
num++;
if (num == should) return;
}
}
int main()
{
//Open();
Close();//scanf,puts,printf not use
//init??????
cin >> (s + 1);
len = strlen(s + 1);
dfs(1, len, 1);
int dep = 1;
while (int(ans[dep + 1].size())) dep++;
cout << dep << endl;
rep1(i, 1, dep)
{
int len = ans[i].size();
rep1(j, 0, len - 1)
{
cout << ans[i][j];
if (j == len - 1)
cout << endl;
else
cout << ' ';
}
}
return 0;
}