【Codeforces 375A】Divisible by Seven
【链接】 我是链接,点我呀:)
【题意】
【题解】
我们先提取出来1,6,8,9各1个 然后把剩余的len-4个数字除了0之外放在前面 那么这len-4个除了0之外的数字组成的十进制数字对7的取余结果肯定是0~6之间。 然后我们用这个取余结果,和1,6,8,9的所有全排列一个一个去试,尝试把排列出来的结果放在这len-4个数字的后面 最后发现取余结果为0~6都能找到一个1,6,8,9的排列,使得它放在他们后面,然后取余结果为0 最后把剩余的0放在1,6,8,9的后面就好。【代码】
import java.io.*;
import java.util.*;
public class Main {
static InputReader in;
static PrintWriter out;
public static void main(String[] args) throws IOException{
//InputStream ins = new FileInputStream("E:\\rush.txt");
InputStream ins = System.in;
in = new InputReader(ins);
out = new PrintWriter(System.out);
//code start from here
new Task().solve(in, out);
out.close();
}
static int N = 50000;
static class Task{
int cnt[] = new int[10];
int a[] = {0,1,6,8,9};
int b[] = new int[10];
boolean bo[] = new boolean[5];
int n;
String s;
int cur = 0;
boolean dfs(int dep,int now) {
if (dep==5) {
int temp = now;
for (int i = 1;i <= 4;i++) {
temp = temp*10 + b[i];
temp = temp%7;
}
if (temp==0) {
for (int i = 1;i <= 4;i++) {
out.print(b[i]);
}
return true;
}
return false;
}
for (int i = 1;i <= 4;i++)
if (!bo[i]) {
bo[i] = true;
b[dep] = a[i];
if (dfs(dep+1,now)) return true;
bo[i] = false;
}
return false;
}
public void solve(InputReader in,PrintWriter out) {
s = in.next();
for (int i = 0;i < (int)s.length();i++) {
int key = s.charAt(i)-'0';
if (key==1 && cnt[1]==0) {
cnt[1] = 1;
}else if (key==6 && cnt[6]==0){
cnt[6] = 1;
}else if (key==8 && cnt[8]==0) {
cnt[8] = 1;
}else if (key==9 && cnt[9]==0) {
cnt[9] = 1;
}else {
cnt[key]++;
if (key!=0) {
out.print(key);
cur = cur * 10 + key;
cur = cur % 7;
}
}
}
dfs(1,cur);
for (int i = 1;i <= cnt[0];i++) {
out.print(0);
}
}
}
static class InputReader{
public BufferedReader br;
public StringTokenizer tokenizer;
public InputReader(InputStream ins) {
br = new BufferedReader(new InputStreamReader(ins));
tokenizer = null;
}
public String next(){
while (tokenizer==null || !tokenizer.hasMoreTokens()) {
try {
tokenizer = new StringTokenizer(br.readLine());
}catch(IOException e) {
throw new RuntimeException(e);
}
}
return tokenizer.nextToken();
}
public int nextInt() {
return Integer.parseInt(next());
}
}
}