【Codeforces 159B】Matchmaker

【链接】 我是链接,点我呀:)
【题意】

笔和笔盖 笔有颜色和直径 笔盖也有颜色和直径 笔盖和笔如果直径相等 那么称为good 如果笔盖和笔直径相等、颜色也相等,那么称为very good 问你怎样安排笔和笔盖才能让good最多的情况下very good也最多.

【题解】

将直径相同的笔和笔盖放在同一个arraylist里面 然后写个hash,将颜色相同的优先配对 剩下的没办法只能委屈配对成"good"

【代码】

import java.io.*;
import java.util.*;

public class Main {
    
    
    static InputReader in;
    static PrintWriter out;
        
    public static void main(String[] args) throws IOException{
        //InputStream ins = new FileInputStream("E:\\rush.txt");
        InputStream ins = System.in;
        in = new InputReader(ins);
        out = new PrintWriter(System.out);
        //code start from here
        new Task().solve(in, out);
        out.close();
    }
    
    static int N = 1000;
    static class Task{
    	
    	class Pair{
    		int x,type;
    		public Pair(int x,int type) {
    			this.x = x;this.type = type;
    		}
    	}
        
        int n,m;
        ArrayList<Pair> g[] = new ArrayList[N+10];
        int cnt[] = new int[N+10];
        
        public void solve(InputReader in,PrintWriter out) {
        	for (int i = 1;i <= N;i++) g[i] = new ArrayList<Pair>();
        	n = in.nextInt();m = in.nextInt();
        	for (int i = 1;i <= n;i++) {
        		int x,y;
        		x = in.nextInt();y = in.nextInt();
        		g[y].add(new Pair(x,1));
        	}
        	for (int j = 1;j <= m;j++) {
        		int x,y;
        		x = in.nextInt();y = in.nextInt();
        		g[y].add(new Pair(x,2));
        	}
        	long ans1 = 0,ans2 = 0;
        	for (int i = 1;i <= N;i++) {
        		for (int j = 1;j <= N;j++) cnt[j] = 0;
        		int len = g[i].size();
        		for (int j = 0;j < len;j++)
        		{
        			Pair temp = g[i].get(j);
        			if (temp.type==1) {
        				cnt[temp.x]++;
        			}
        		}
        		long pair_beautiful = 0,pair_normal=0;
        		for (int j = 0;j < len;j++)
        		{
        			Pair temp = g[i].get(j);
        			if (temp.type==2) {
        				if (cnt[temp.x]>0) {
        					cnt[temp.x]--;
							pair_beautiful++;
        				}else pair_normal++;
        			}
        		}
        		long temp1 = 0;
        		for (int j = 1;j <= N;j++) {
        			temp1+=cnt[j];
        		}
        		pair_normal = Math.min(temp1, pair_normal);
        		ans1+=pair_normal;ans2+=pair_beautiful;
        	}
        	out.println((ans1+ans2)+" "+ans2);
        }
    }

    

    static class InputReader{
        public BufferedReader br;
        public StringTokenizer tokenizer;
        
        public InputReader(InputStream ins) {
            br = new BufferedReader(new InputStreamReader(ins));
            tokenizer = null;
        }
        
        public String next(){
            while (tokenizer==null || !tokenizer.hasMoreTokens()) {
                try {
                tokenizer = new StringTokenizer(br.readLine());
                }catch(IOException e) {
                    throw new RuntimeException(e);
                }
            }
            return tokenizer.nextToken();
        }
        
        public int nextInt() {
            return Integer.parseInt(next());
        }
    }
}
posted @ 2019-03-10 20:44  AWCXV  阅读(162)  评论(0编辑  收藏  举报