【Codeforces 522A】Reposts
【链接】 我是链接,点我呀:)
【题意】
【题解】
用map把每个人的英文都转成小写的 然后从map中获取单词的标号 转换成图。 然后从根节点开始dfs即可【代码】
import java.io.*;
import java.util.*;
public class Main {
static InputReader in;
static PrintWriter out;
public static void main(String[] args) throws IOException{
//InputStream ins = new FileInputStream("E:\\rush.txt");
InputStream ins = System.in;
in = new InputReader(ins);
out = new PrintWriter(System.out);
//code start from here
new Task().solve(in, out);
out.close();
}
static int N = (int)400;
static class Task{
int n,cnt,ans = 0;
ArrayList []g;
void dfs(int x,int dep) {
ans = Math.max(ans,dep);
for (int i = 0;i < (int)g[x].size();i++) {
int y = (int)g[x].get(i);
dfs(y,dep+1);
}
}
public void solve(InputReader in,PrintWriter out) {
g = new ArrayList[N+10];
HashMap<String,Integer> dic = new HashMap<String,Integer>();
for(int i = 1;i <= N;i++)g[i] = new ArrayList();
n = in.nextInt();
for (int i = 0;i < n;i++) {
StringBuilder sb1 = new StringBuilder();
StringBuilder sb2 = new StringBuilder();
String s1,s2;
s1 = in.next();s2 = in.next();s2 = in.next();
char key;
for (int j = 0;j < (int)s1.length();j++) {
if (s1.charAt(j)>='A' && s1.charAt(j)<='Z') {
key = (char)(s1.charAt(j)-'A'+'a');
sb1.append(key);
}else {
key =(char)s1.charAt(j);
sb1.append(s1.charAt(j));
}
}
s1 = sb1.toString();
for (int j = 0;j < (int)s2.length();j++) {
if (s2.charAt(j)>='A' && s2.charAt(j)<='Z') {
key = (char)(s2.charAt(j)-'A'+'a');
sb2.append(key);
}else {
key =(char)s2.charAt(j);
sb2.append(key);
}
}
s2 = sb2.toString();
if (!dic.containsKey(s1)) {
dic.put(s1, ++cnt);
}
if (!dic.containsKey(s2)) {
dic.put(s2, ++cnt);
}
int x = dic.get(s1),y = dic.get(s2);
g[y].add(x);
}
dfs(dic.get("polycarp"),1);
out.println(ans);
}
}
static class InputReader{
public BufferedReader br;
public StringTokenizer tokenizer;
public InputReader(InputStream ins) {
br = new BufferedReader(new InputStreamReader(ins));
tokenizer = null;
}
public String next(){
while (tokenizer==null || !tokenizer.hasMoreTokens()) {
try {
tokenizer = new StringTokenizer(br.readLine());
}catch(IOException e) {
throw new RuntimeException(e);
}
}
return tokenizer.nextToken();
}
public int nextInt() {
return Integer.parseInt(next());
}
}
}