【Codeforces 429B】Working out

【链接】 我是链接,点我呀:)
【题意】

两个人,一个人在左上角,一个人在左下角。 左上角要到右下角去 左下角要到右上角去 只能走到相邻的格子(不能往回走,即一个往右下,一个往右上走) 要求这两个人必须要在这个n*m的格子中选择一个格子作为休息点. (两条路径只能有一个一样的点) 问最多能拿到多少分数(每个格子上有一个分数值)

【题解】

 会发现只有②和③不会重复走 则设f[p][i][j]分别为从左上、左下、右上、右下出发,到达点(i,j)的最大分数值 枚举休息点在什么地方 根据上图取答案的最大值就好

【代码】

import java.io.*;
import java.util.*;

public class Main {
	
	
	static InputReader in;
	static PrintWriter out;
		
	public static void main(String[] args) throws IOException{
		//InputStream ins = new FileInputStream("E:\\rush.txt");
		InputStream ins = System.in;
		in = new InputReader(ins);
		out = new PrintWriter(System.out);
		//code start from here
		new Task().solve(in, out);
		out.close();
	}
	
	static int N = (int)1e3;
	static class Task{
		public void solve(InputReader in,PrintWriter out) {
			int n,m;
			int [][]a = new int[N+10][N+10];
			int [][][]f = new int[4][N+10][N+10];
			n = in.nextInt();m = in.nextInt();
			for (int i = 1;i <= n;i++)
				for (int j = 1;j <= m;j++)
					a[i][j] = in.nextInt();
			
			//f[0]
			for (int i = 1;i <= n;i++)
				for (int j = 1;j <= m;j++)
					f[0][i][j] = Math.max(f[0][i-1][j], f[0][i][j-1])+a[i][j];
			
			//f[1]
			for (int i = 1;i <= n;i++)
				for (int j = m;j >= 1;j--)
					f[1][i][j] = Math.max(f[1][i-1][j], f[1][i][j+1])+a[i][j];
			
			//f[2]
			for (int i = n;i >= 1;i--)
				for (int j = 1;j <= m;j++)
					f[2][i][j] = Math.max(f[2][i][j-1], f[2][i+1][j])+a[i][j];
			
			//f[3]
			//f[0]
			for (int i = n;i >= 1;i--)
				for (int j = m;j >= 1;j--)
					f[3][i][j] = Math.max(f[3][i+1][j], f[3][i][j+1])+a[i][j];
			
			int ans = 0;
			for (int i = 1;i <= n;i++)
				for (int j = 1;j <= m;j++) {
					//(i,j)
					if (i>=2 && i<=n-1 && j>=2 && j <= m-1) {
						//plan 2
						int temp0,temp1,temp2,temp3;
						temp0 = f[0][i-1][j];
						temp1 = f[1][i][j+1];
						temp2 = f[2][i][j-1];
						temp3 = f[3][i+1][j];
						ans = Math.max(ans, temp0+temp1+temp2+temp3);
						
						//plan 3
						temp0 = f[0][i][j-1];
						temp1 = f[1][i-1][j];
						temp2 = f[2][i+1][j];
						temp3 = f[3][i][j+1];
						ans = Math.max(ans, temp0+temp1+temp2+temp3);
					}
				}
			out.println(ans);
		}
	}

	

	static class InputReader{
		public BufferedReader br;
		public StringTokenizer tokenizer;
		
		public InputReader(InputStream ins) {
			br = new BufferedReader(new InputStreamReader(ins));
			tokenizer = null;
		}
		
		public String next(){
			while (tokenizer==null || !tokenizer.hasMoreTokens()) {
				try {
				tokenizer = new StringTokenizer(br.readLine());
				}catch(IOException e) {
					throw new RuntimeException(e);
				}
			}
			return tokenizer.nextToken();
		}
		
		public int nextInt() {
			return Integer.parseInt(next());
		}
	}
}