1. 题目描述
打印蛇形矩阵
2. 思路
- 状态机模拟
- 我称之为模拟优化,因为代码少,简洁,优化
3. 代码(模拟优化)
class Solution {
public:
vector<int> spiralOrder(vector<vector<int>>& matrix) {
int n, m;
if(!(n = matrix.size()) || !(m = matrix[0].size())) return {};
vector<int> res;
int left = 0, right = m - 1;
int top = 0, down = n - 1;
while(left <= right && top <= down) {
cout << left << ' ' << right << endl << top << ' ' << down << endl;
for(int i = left; i <= right; i ++ ) res.emplace_back(matrix[top][i]);
for(int i = top + 1; i <= down; i ++ ) res.emplace_back(matrix[i][right]);
if(top != down) // 特判,不然同一行,从左到右走和从右到左走会重复
for(int i = right - 1; i >= left; i -- ) res.emplace_back(matrix[down][i]);
if(left != right) // 特判,不然同一行从上到下走和从下到上走重复了
for(int i = down - 1; i >= top + 1; i -- ) res.emplace_back(matrix[i][left]);
left ++ , right -- , down -- , top ++ ;
}
return res;
}
};
/*
[[1]]
[[1,2],[3,4]]
[[1,2,3],[4,5,6],[7,8,9]]
[[1,2,3,4],[5,6,7,8],[9,10,11,12]]
[[1,2,3,4,11],[5,6,7,8,22],[9,10,11,12,33],[44,55,66,77,88]]
1 2 3 4
5 6 7 8
9 10 11 12
*/