摘要： https://blog.csdn.net/u012700322/article/details/51784412 https://wiki.ros.org/message_filters https://blog.csdn.net/muyiyushan/article/details/118418 阅读全文

摘要： https://blog.csdn.net/jdsjlzx/article/details/98654951 https://blog.csdn.net/QH_JAVA/article/details/77979622?spm=1001.2101.3001.6650.1&utm_medium=dis 阅读全文

摘要： https://blog.csdn.net/dangzhangjing97/article/details/81279862?spm=1001.2101.3001.6661.1&utm_medium=distribute.pc_relevant_t0.none-task-blog-2%7Edefau 阅读全文

摘要： https://blog.csdn.net/shuiyixin/article/details/83151977/ https://blog.csdn.net/hankai1024/article/details/8011306?spm=1001.2101.3001.6650.2&utm_mediu 阅读全文

摘要： atan 和 atan2 都是求反正切函数，如：有两个点 point(x1,y1), 和 point(x2,y2); 那么这两个点形成的斜率的角度计算方法分别是： float angle = atan( (y2-y1)/(x2-x1) ); 或 float angle = atan2( y2-y1, 阅读全文

摘要： listener.lookupTransform("/turtle2", "/turtle1", ros::Time(0), transform);订阅的是 turtle2 到 turtle1 的位姿变换 即 turtle1 在 turtle2 坐标系下的位姿https://www.cnblogs. 阅读全文

摘要： https://blog.csdn.net/u011442726/article/details/94588440 https://blog.csdn.net/weixin_42310154/article/details/119004977 www.baidu.com/link?url=_mZH2 阅读全文

摘要： https://blog.csdn.net/weixin_44212574/article/details/89043854 https://blog.csdn.net/passion_wu128/article/details/38511957?spm=1001.2101.3001.6650.10 阅读全文

摘要： https://blog.csdn.net/ccf19881030/article/details/102596938 https://blog.csdn.net/sunyoop/article/details/79295480?spm=1001.2101.3001.6650.4&utm_mediu 阅读全文

摘要： https://blog.csdn.net/yyz_1987/article/details/123853588?spm=1001.2101.3001.6650.10&utm_medium=distribute.pc_relevant.none-task-blog-2%7Edefault%7EBlo 阅读全文