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摘要: Feng ShuiTime Limit: 2000MSMemory Limit: 65536KTotal Submissions: 4532Accepted: 1390Special JudgeDescriptionFeng shui is the ancient Chinese practice ... 阅读全文
posted @ 2015-02-17 14:28 Doli 阅读(88) 评论(0) 推荐(0) 编辑
摘要: Most Distant Point from the SeaTime Limit: 5000MSMemory Limit: 65536KTotal Submissions: 4102Accepted: 1921Special JudgeDescriptionThe main land of Jap... 阅读全文
posted @ 2015-02-17 10:00 Doli 阅读(145) 评论(0) 推荐(0) 编辑
摘要: Art GalleryTime Limit: 1000MSMemory Limit: 10000KTotal Submissions: 5705Accepted: 2410DescriptionThe art galleries of the new and very futuristic buil... 阅读全文
posted @ 2015-02-16 14:00 Doli 阅读(146) 评论(0) 推荐(0) 编辑
摘要: Building FenceTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 65535/65535 K (Java/Others)Total Submission(s): 1848Accepted Submission(s): 383Speci... 阅读全文
posted @ 2015-02-15 15:23 Doli 阅读(137) 评论(0) 推荐(0) 编辑
摘要: Quoit DesignTime Limit: 10000/5000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 34731Accepted Submission(s): 9062Prob... 阅读全文
posted @ 2015-02-14 17:45 Doli 阅读(1942) 评论(0) 推荐(0) 编辑
摘要: TriangleTime Limit: 3000MSMemory Limit: 30000KTotal Submissions: 8406Accepted: 2490DescriptionGiven n distinct points on a plane, your task is to find... 阅读全文
posted @ 2015-02-14 16:44 Doli 阅读(113) 评论(0) 推荐(0) 编辑
摘要: 1、线段上格点问题格点:就是平面上坐标为整数的点。问题:平面中一条线段上有多少个整数点?2、线段上的格点数算法//求数a、b的最大公因数int gcd ( int a,int b){ if(b==0) return a;else return gcd(b,a%b);}//线段AB上的格点个数由下列程... 阅读全文
posted @ 2015-02-14 11:01 Doli 阅读(189) 评论(0) 推荐(0) 编辑
摘要: A Round Peg in a Ground HoleTime Limit: 1000MSMemory Limit: 10000KTotal Submissions: 5400Accepted: 1713DescriptionThe DIY Furniture company specialize... 阅读全文
posted @ 2015-02-13 21:12 Doli 阅读(102) 评论(0) 推荐(0) 编辑
摘要: IntersectionTime Limit: 1000MSMemory Limit: 10000KTotal Submissions: 12156Accepted: 3155DescriptionYou are to write a program that has to decide wheth... 阅读全文
posted @ 2015-02-13 16:13 Doli 阅读(107) 评论(0) 推荐(0) 编辑
摘要: The DoorsTime Limit: 1000MSMemory Limit: 10000KTotal Submissions: 6617Accepted: 2634DescriptionYou are to find the length of the shortest path through... 阅读全文
posted @ 2015-02-13 14:25 Doli 阅读(102) 评论(0) 推荐(0) 编辑
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