UESTC 594 我要长高 dp单调队列

//戳这里:594

//补一发之前的单调队列 dp

 1 #include "bits/stdc++.h"
 2 using namespace std;
 3 int N, C;
 4 int h[50010];
 5 
 6 int dp[50010][110];
 7 struct Queue
 8 {
 9     int value;
10 }q[110], tmp;
11 int front, rear;
12 
13 //j > k 时,
14 //dp[i][j] = min(dp[i - 1][k] + (j - k) * C + (j - h[i]) * (j - h[i]));
15 //dp[i][j] = min(dp[i - 1][k] - k * C) + j * C + (j - h[i]) * (j - h[i]);
16 
17 int main()
18 {
19     while(scanf("%d%d", &N, &C) != EOF) {
20         //初始化
21         memset(dp, 0x3f, sizeof(dp[0]) * (N + 1));
22         //输入
23         int i;
24         for(i = 1; i <= N; ++i) {
25             scanf("%d", &h[i]);
26         }
27         //k 不需要优化的情况
28         int j;
29         for(j = h[1]; j <= 100; ++j) {
30             dp[1][j] = (j - h[1]) * (j - h[1]);
31         }
32         //从 2 开始dp
33         for(i = 2; i <= N; ++i) {
34             front = rear = 1;
35             for(j = h[i - 1]; j <= 100; ++j) {
36                 tmp.value = dp[i - 1][j] - j * C;
37                 for( ; front < rear && tmp.value < q[rear - 1].value; --rear);
38                 q[rear++] = tmp;
39                 if(j >= h[i]) {
40                     dp[i][j] = q[front].value + j * C + (j - h[i]) * (j - h[i]);
41                 }
42             }
43             front = rear = 1;
44             for(j = 100; j >= h[i]; --j) {
45                 tmp.value = dp[i - 1][j] + j * C;
46                 for( ; front < rear && tmp.value < q[rear - 1].value; --rear);
47                 q[rear++] = tmp;
48                 dp[i][j] = min(dp[i][j], q[front].value - j * C + (j - h[i]) * (j - h[i]));
49             }
50         }
51         int res = 0x3f3f3f3f;
52         for(i = 1; i <= 100; ++i) {
53             res = min(res, dp[N][i]);
54         }
55         printf("%d\n", res);
56     }
57 }

 

posted @ 2015-05-08 15:55  AC_Phoenix  阅读(188)  评论(0编辑  收藏  举报