PAT 1108 Finding Average

The basic task is simple: given N real numbers, you are supposed to calculate their average. But what makes it complicated is that some of the input numbers might not be legal. A legal input is a real number in [−1000,1000] and is accurate up to no more than 2 decimal places. When you calculate the average, those illegal numbers must not be counted in.

Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (≤100). Then N numbers are given in the next line, separated by one space.

Output Specification:
For each illegal input number, print in a line ERROR: X is not a legal number where X is the input. Then finally print in a line the result: The average of K numbers is Y where K is the number of legal inputs and Y is their average, accurate to 2 decimal places. In case the average cannot be calculated, output Undefined instead of Y. In case K is only 1, output The average of 1 number is Y instead.

Sample Input 1:

7
5 -3.2 aaa 9999 2.3.4 7.123 2.35

Sample Output 1:

ERROR: aaa is not a legal number
ERROR: 9999 is not a legal number
ERROR: 2.3.4 is not a legal number
ERROR: 7.123 is not a legal number
The average of 3 numbers is 1.38

Sample Input 2:

2
aaa -9999

Sample Output 2:

ERROR: aaa is not a legal number
ERROR: -9999 is not a legal number
The average of 0 numbers is Undefined

#include<iostream> //sscanf,sprintf的运用
#include<string.h>
using namespace std;
int main(){
	char a[50], b[50];
	double sum, temp;
	int N, cnt=0;
	cin>>N;
	for(int i=0; i<N; i++){
		scanf("%s",a);
		sscanf(a,"%lf",&temp);
		sprintf(b,"%.2lf",temp);
		int flag=0;
		for(int j=0; j<strlen(a); j++){
			if(a[j]!=b[j])
				flag=1;
		}
		 if(flag || temp < -1000 || temp > 1000) {
            printf("ERROR: %s is not a legal number\n", a);
            continue;
        } else {
            sum += temp;
            cnt++;
        }
	}
	if(cnt == 1) {
        printf("The average of 1 number is %.2lf", sum);
    } else if(cnt > 1) {
        printf("The average of %d numbers is %.2lf", cnt, sum / cnt);
    } else {
        printf("The average of 0 numbers is Undefined");
    }
    return 0;
}