巴什博弈----hdu2147-----较难

kiki's game

Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 40000/10000 K (Java/Others)
Total Submission(s): 8946    Accepted Submission(s): 5335

Problem Description

Recently kiki has nothing to do. While she is bored, an idea appears in his mind, she just playes the checkerboard game.The size of the chesserboard is n*m.First of all, a coin is placed in the top right corner(1,m). Each time one people can move the coin into the left, the underneath or the left-underneath blank space.The person who can't make a move will lose the game. kiki plays it with ZZ.The game always starts with kiki. If both play perfectly, who will win the game?

 

 

Input

Input contains multiple test cases. Each line contains two integer n, m (0<n,m<=2000). The input is terminated when n=0 and m=0.

 

 

Output

If kiki wins the game printf "Wonderful!", else "What a pity!".

 

 

Sample Input

5 3 5 4 6 6 0 0

 

 

Sample Output

What a pity! Wonderful! Wonderful!

 题意:给你一个 n*m的方阵 然后 有两个叫kiki和zz的人  kiki 每次都从 方阵的右上角开始 走 然后 zz 再开始走 zz必须在上次kiki走的空的 右方 或者 下方 或者右下方,这三个方向 

谁最先走到 左下方 谁就是胜利者  .

这个大大 讲得很不错  http://blog.csdn.net/no_retreats/article/details/7900654

下面附上代码

#include<stdio.h>
int main()
{
    int n,m;
    while(scanf("%d%d",&n,&m)&&!(n==0&&m==0))
    {
        if(n%2!=0&&m%2!=0)
            printf("What a pity!\n");
        else
            printf("Wonderful!\n");
    }
}