Cutting an integer means to cut a K digits long integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of A and B, as 167334 / (167 x 334) = 3. Given an integer Z, you are supposed to test if it is such an integer.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (<= 20). Then N lines follow, each gives an integer Z (10<=Z<=231). It is guaranteed that the number of digits of Z is an even number.
Output Specification:
For each case, print a single line "Yes" if it is such a number, or "No" if not.
Sample Input:3 167334 2333 12345678Sample Output:
Yes No No
代码:
#include <cstdio> #include <iostream> #include <algorithm> #include <cstring> #include <map> using namespace std; int coun(int d) { int c = 0; while(d) { c ++; d /= 10; } return c; } int main() { int n,d; scanf("%d",&n); while(n --) { scanf("%d",&d); int s = coun(d),p = 1; s /= 2; for(int i = 0;i < s;i ++) p *= 10; s = (d/p)*(d%p);///如果是0不能做取模 if(s && d % s == 0)printf("Yes\n"); else printf("No\n"); } }
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