摘要: 矩阵连乘核心代码1 for(int i=0;imax) 34 max=tmp; 35 if(tmpmax) 38 max=tmp; 39 if(tmpmax) 42 max=tmp; 43 if(tmpmax) 46 ... 阅读全文
posted @ 2014-08-13 23:11 daydaycode 阅读(974) 评论(0) 推荐(0) 编辑
摘要: http://poj.org/problem?id=1082Time Limit:1000MSMemory Limit:10000KTotal Submissions:4820Accepted:2273DescriptionAdam and Eve enter this year's ACM Int... 阅读全文
posted @ 2014-08-13 09:51 daydaycode 阅读(194) 评论(0) 推荐(0) 编辑