Python开发笔记之-字符串函数
1.首字母大写
>>> s = 'yuanzhumuban' >>> s.capitalize() 'yuanzhumuban'
>>> s = 'my name is yuanzhumuban, age is 20' >>> s 'my name is yuanzhumuban, age is 20' >>> s.replace( '20', '30' ) 'my name is yuanzhumuban, age is 30' >>> s 'my name is yuanzhumuban, age is 20' >>>
查帮助:
>>> help( str.replace )
如果是面向过程的函数用法,直接help( 函数名 ),如help( abs )
replace(...) S.replace(old, new[, count]) -> string Return a copy of string S with all occurrences of substring old replaced by new. If the optional argument count is given, only the first count occurrences are replaced.
接受3个参数,第一个需要替换的字符,第二个用什么字符去替换,第三个替换的次数,如果不传,默认全部替换
str = '121212' str.replace( '1', 'g' ) 'g2g2g2' str.replace( '1', 'g', 1 ) 'g21212' str.replace( '1', 'g', 2 ) 'g2g212' str.replace( '1', 'g', 3 ) 'g2g2g2'
1 >>> ip='127.0.0.1' 2 >>> ip 3 '127.0.0.1' 4 >>> ip.split( '.' ) 5 ['127', '0', '0', '1'] 6 >>> ip.split( '.', 1 ) 7 ['127', '0.0.1'] 8 >>> ip.split( '.', 2 ) 9 ['127', '0', '0.1'] 10 >>> ip.split( '.', 3 ) 11 ['127', '0', '0', '1'] 12 >>>
1 >>> import string 2 >>> help( string.capitalize ) 3 4 >>> s = 'ghostwu' 5 >>> string.capitalize( s ) 6 'Ghostwu'
1 >>> import string 2 >>> s = 'my name is ghostwu, age is 20' 3 >>> string.replace( s, '20', '30' ) 4 'my name is ghostwu, age is 30' 5 >>> ip 6 '127.0.0.1' 7 >>> string.split( ip, '.' ) 8 ['127', '0', '0', '1'] 9 >>> string.split( ip, '.', 1 ) 10 ['127', '0.0.1'] 11 >>>
千行代码,Bug何处藏。 纵使上线又怎样,朝令改,夕断肠。