Python应用之-修改通讯录
#-*- coding:utf-8 -*- import sqlite3 #打开本地数据库用于存储用户信息 conn = sqlite3.connect('mysql_person.db') #在该数据库下创建表,创建表的这段代码在第一次执行后需要注释掉,否则再次执行程序会一直提示:该表已存在 conn.execute ('''CREATE TABLE MT_table1( ID INTEGER PRIMARY KEY AUTOINCREMENT, NAME TEXT NOT NULL, AGE INT NOT NULL, ADDRESS CHAR(50), SALARY REAL, PhoneNumber INT NOT NULL);''') print "Table created successfully"; #增加用户信息 def insert(): USER_NAME = raw_input('请输入用户昵称:') cursor = conn.execute("SELECT name from MT_table1 where name = '%s';"%USER_NAME) for row in cursor: if USER_NAME == row[0]: print "sorry,改用户名已存在,请重新输入用户名" break else: AGE = input('请输入年龄:') ADDRESS = raw_input('请输入用户地址:') SALARY = input('请输入用户薪水:') PhoneNumber = input("请输入联系方式:") #为避免代码太长,以下我用字符串的连接特性将代码缩短 sql1 = 'INSERT INTO MT_table1(NAME,AGE,ADDRESS,SALARY,PhoneNumber)' sql1 += 'VALUES("%s","%d","%s","%d","%d");'%(USER_NAME,AGE,ADDRESS,SALARY,PhoneNumber) conn.execute(sql1) conn.commit() print "Records insert successfully" #删除用户信息 def delete(): delete_name = raw_input("请输入所要删除的联系人姓名:") cursor = conn.execute("SELECT name from MT_table1 where name = '%s';"%delete_name) for row in cursor: if delete_name == row[0]: conn.execute("DELETE from MT_table1 where name = '%s';"%delete_name) conn.commit() print "Records delete successfully" break else: print "sorry,不存在该用户" #修改用户信息 def modify(): update_name = raw_input("请输入要修改用户的姓名:") sql6 = "SELECT name from MT_table1 where name = '%s';"%update_name cursor = conn.execute(sql6) for row in cursor: if update_name == row[0]: New_addr = raw_input("请输入要修改用户的新地址:") New_age = input("请输入要修改用户的新年龄:") New_salary = input("请输入要修改用户的新薪水:") New_num = input("输入要修改用户的新号码:") sql3 = "UPDATE MT_table1 set address = '%s',age = '%d',salary = '%d',PhoneNumber = '%d' where \ name = '%s';"%(New_addr,New_age,New_salary,New_num,update_name) conn.execute(sql3) conn.commit() print "修改成功" sql5 = "SELECT id, name, age,address, salary ,PhoneNumber from MT_table1 where name = '%s';"%update_name cursor = conn.execute(sql5) for row in cursor: print "ID = ", row[0] print "NAME = ", row[1] print "AGE = ",row[2] print "ADDRESS = ", row[3] print "SALARY = ", row[4] print "PhoneNumber = ",row[5], "\n" break else: print "sorry,不存在该用户信息" #查询用户信息 def search(): conn = sqlite3.connect('mysql_person.db') search_name = raw_input('请输入要查询的用户姓名') sql2 = "SELECT id,name,age, address, salary ,PhoneNumber from MT_table1 where name= '%s';" % (search_name) cursor = conn.execute(sql2) for row in cursor: print "ID = ", row[0] print "NAME = ", row[1] print "AGE = ",row[2] print "ADDRESS = ", row[3] print "SALARY = ", row[4] print "PhoneNumber = ",row[5], "\n" break else: print "sorry,没有该用户信息" #显示所有用户信息 def showall(): cursor = conn.execute("SELECT id, name,age, address, salary ,PhoneNumber from MT_table1") for row in cursor: print "ID = ", row[0] print "NAME = ", row[1] print "AGE = ",row[2] print "ADDRESS = ", row[3] print "SALARY = ", row[4] print "PhoneNumber = ",row[5], "\n" print "Operation done successfully"; cursor = conn.execute("select count(*) from MT_table1;") for row in cursor: print "一共有%d个用户"%row[0] def menu(): print '1.新增联系人' print '2.删除联系人' print '3.修改联系人' print '4.查询联系人' print '5.显示所有联系人' print '6.退出程序' print 'What do you want to do?' while True: menu() x = raw_input('请输入您的选择菜单号:') if x == '1': insert() continue if x == '2': delete() continue if x == '3': modify() continue if x == '4': search() continue if x == '5': showall() continue if x == '6': print "谢谢使用!" exit() continue else: print "输入的选项不存在,请重新输入!" continue
千行代码,Bug何处藏。 纵使上线又怎样,朝令改,夕断肠。