摘要: #2017102 import time start = time.process_time() a = list(range(1000000,9999999)) a2 = [str(i) for i in a] count =1 for i in a2: if i==i[::-1] and 1 <= int(i[4:6])<=12: print(count,'',i[:4],'年',i[4:6] 阅读全文
posted @ 2019-10-04 23:01 Yuki-Yang 阅读(155) 评论(0) 推荐(0) 编辑