比较有趣的C语言小程序
1.判断是否是闰年：
#include <stdio.h> int main(void) { int year, a; printf("Please enter the year：\n"); scanf("%d",&year); if (year % 400 == 0) a = 1; else { if (year % 4 == 0 && year % 100 != 0) a = 1; else a = 0; } if (a == 1) printf("%d is a leap year\n", year); else printf("%d not a leap year\n", year); return 0; }
2.判断一个日期是周几，有两种算法
1 #include "stdio.h" 2 int day_of_week1(int y, int m, int d)//使用的是蔡勒公式 3 { 4 if (m < 3) 5 { 6 y--; 7 m += 12; 8 } 9 return ((y%100+(y%100)/4+(y/100)/4-2*(y/100)+(26*(m+1))/10+d-1)%7); 10 } 11 12 int day_of_week2(int y, int m, int d)// 13 { 14 int t[12]={0,3,2,5,0,3,5,1,4,6,2,4}; 15 y -= m < 3; 16 return ((y + y / 4 - y / 100 + y / 400 + t[m - 1] + d) % 7); 17 } 18 19 int main(void) 20 { 21 int a = 3, y=2020, m=1, d=1, w1 = 0,w2; 22 printf("%d-%d-%d\n", y, m, d); 23 w1 = day_of_week1(y, m, d); 24 printf("星期%d", w); 25 w2 = day_of_week2(y, m, d); 26 printf("星期%d", w); 27 return 0; 28 }
3.打印心代码（转自一位不知道的大佬）
1 #include "stdio.h" 2 #include <math.h> 3 float f(float x, float y, float z) 4 { 5 float a = x * x + 9.0f / 4.0f * y * y + z * z - 1; 6 return a * a * a - x * x * z * z *z- 9.0f / 80.0f * y * y * z * z * z; 7 } 8 float h(float x, float z) 9 { 10 for (float y = 1.0f; y >= 0.0f; y -= 0.001f) 11 if (f(x, y, z) <= 0.0f) 12 return y; 13 return 0.0f; 14 } 15 int main(void) 16 { 17 for (float z = 1.5f; z > -1.5f; z -= 0.05f) 18 { 19 for (float x = -1.5f; x < 1.5f; x+= 0.025f) 20 { 21 float v = f(x, 0.0f, z); 22 if(v <= 0.0f) 23 { 24 float y0 = h(x,z); 25 float ny = 0.01f; 26 float nx = h(x + ny, z) - y0; 27 float nz = h(x, z+ny) - y0; 28 float nd = 1.0f /sqrtf(nx*nx + ny*ny + nz*nz); 29 float d = (nx+ny-nz) * nd *0.5f + 0.5f; 30 putchar(".:-=+*#%@"[(int)(d*5.0f)]); 31 } 32 else 33 putchar(' '); 34 } 35 putchar(' '); 36 } 37 for (int i = 5; i >0;){} 38 }
4.这个建议自己试试，很好玩。
#include <stdio.h> #include <stdlib.h> #define decode(p,r,i,n,t,f) r##f##r##i##t##p #define puts decode(m,s,t,o,e,y) int main() { puts((char*)(const double[]){1.3553894309652565e+224,6.952439113111912e-308}); return 0; }
