第三次作业-有进度条圆周率计算

代码:

#JDTYZL.py
import math
import time
scale=14
s,m,=1,2
print("执行开始".center(scale//2, "-"))
start = time.perf_counter()
for i in range(scale+1):
s=math.sqrt((1-math.sqrt(1-pow(s,2)))/2)
m=m*2
a = '*' * i
b = '.' * (scale - i)
c = (i/scale)*100
dur = time.perf_counter() - start
print("\r{:^3.0f}%[{}->{}]{:.2f}s".format(c,a,b,dur))
time.sleep(0.1)
Pi=s*m
print("Pi值是{}".format(Pi))
print("\n"+"执行结束".center(scale//2,'-'))

posted @ 2020-03-22 21:16  youto有病  阅读(123)  评论(0编辑  收藏  举报