golang使用slice中遇到的坑

package main

import (
	"fmt"
)

func sliceFunc(i []int, num int) []int {
	for j := 0; j < num; j++ {
		i = append(i, 3)
	}
	i[0] = num
	return i
}
func main() {
	s := make([]int, 0, 3)
	s = append(s, 1)
	fmt.Printf("cap=%d\ts=%v\n",cap(s),s)
	fmt.Println("=========")
	s1 := sliceFunc(s, 2)
	fmt.Printf("cap=%d\ts=%v\n",cap(s),s)
	fmt.Printf("cap=%d\ts1=%v\n",cap(s1),s1)
	fmt.Println("=========")
	s2 := sliceFunc(s, 3)
    fmt.Printf("cap=%d\ts=%v\n",cap(s),s)
	fmt.Printf("cap=%d\ts1=%v\n",cap(s1),s1)
	fmt.Printf("cap=%d\ts1=%v",cap(s2),s2)
}
//当切片扩容的时候会导致slice重新分配内存地址,所有S1改变了的s[0]的值,而s2并没有改变

  原因:切片扩容的时候会导致slice重新分配内存地址

posted @ 2016-08-28 14:08  ZJJ2DSN  阅读(1343)  评论(0编辑  收藏  举报