Loading

奇妙程序员

一些好玩的程序~

love

let x,y,a,str;
for(y=1.5; y>-1.5; y-=0.1){
	str = '';
	for(x=-1.5;x<1.5;x+=0.05){
		a = x*x + y*y - 1;
		str += (a*a*a - x*x*y*y*y < 0.0 ? '*': ' ');
	}
	console.log(str);
}

情人节玫瑰花

rose.html

<!DOCTYPE HTML>
<html>  
<head>  
<title>Rose</title>  
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">  
</head>  
<body style="margin-left:350px">  
<canvas id="c"></canvas>  
<script>  
    var b = document.body;  
    var c = document.getElementsByTagName('canvas')[0];  
    var a = c.getContext('2d');  
    document.body.clientWidth;  
</script>  
<script>  

with(m=Math)C=cos,S=sin,P=pow,R=random;c.width=c.height=f=600;h=-250;function p(a,b,c){if(c>60)return[S(a*7)*(13+5/(.2+P(b*4,4)))-S(b)*50,b*f+50,625+C(a*7)*(13+5/(.2+P(b*4,4)))+b*400,a*1-b/2,a];A=a*2-1;B=b*2-1;if(A*A+B*B<1){if(c>37){n=(j=c&1)?6:4;o=.5/(a+.01)+C(b*125)*3-a*300;w=b*h;return[o*C(n)+w*S(n)+j*610-390,o*S(n)-w*C(n)+550-j*350,1180+C(B+A)*99-j*300,.4-a*.1+P(1-B*B,-h*6)*.15-a*b*.4+C(a+b)/5+P(C((o*(a+1)+(B>0?w:-w))/25),30)*.1*(1-B*B),o/1e3+.7-o*w*3e-6]}if(c>32){c=c*1.16-.15;o=a*45-20;w=b*b*h;z=o*S(c)+w*C(c)+620;return[o*C(c)-w*S(c),28+C(B*.5)*99-b*b*b*60-z/2-h,z,(b*b*.3+P((1-(A*A)),7)*.15+.3)*b,b*.7]}o=A*(2-b)*(80-c*2);w=99-C(A)*120-C(b)*(-h-c*4.9)+C(P(1-b,7))*50+c*2;z=o*S(c)+w*C(c)+700;return[o*C(c)-w*S(c),B*99-C(P(b, 7))*50-c/3-z/1.35+450,z,(1-b/1.2)*.9+a*.1, P((1-b),20)/4+.05]}}setInterval('for(i=0;i<1e4;i++)if(s=p(R(),R(),i%46/.74)){z=s[2];x=~~(s[0]*f/z-h);y=~~(s[1]*f/z-h);if(!m[q=y*f+x]|m[q]>z)m[q]=z,a.fillStyle="rgb("+~(s[3]*h)+","+~(s[4]*h)+","+~(s[3]*s[3]*-80)+")",a.fillRect(x,y,1,1)}',0)  

</script>  
</body>  
</html>

详见：https://blog.csdn.net/u012495579/article/details/71081720

posted @ 2020-02-28 22:17  飞鸿影  阅读(379)  评论(0)  编辑  收藏  举报