Oracle分组函数和连接子查询

作者:gqk:


 什么是组函数:

用于一组数据,并对一组数据返回一个值:

组函数类型:

  • AVG:求平均值
  • COUNT:计数
  • MAX:最大值
  • MIN:最小值
  • SUM:求和

--查询所有工资的总和

SELECT SUM(salary) FROM employees;

--组函数

SELECT SUM(salary),AVG(salary),MAX(salary),MIN(salary),COUNT(salary) 
FROM employees
WHERE department_id=50;


--所有组函数都是忽略空值的

SELECT COUNT(commission_pct) FROM employees;

--查询所有没有奖金的人数

SELECT COUNT(*)-COUNT(commission_pct) FROM employees;
SELECT COUNT(*) FROM employees WHERE commission_pct IS NULL;

--查询部门的总数(统计不重复的计数)

SELECT COUNT(DISTINCT department_id) FROM employees;
--以下是错误的写法,两列的行数不兼容
--SELECT employee_id,SUM(salary) FROM employees;

分组查询:

--查询每个部门的ID,员工工资总和,最高工资

SELECT department_id,SUM(salary) sal_sum,MAX(salary) 
FROM employees
WHERE department_id IS NOT NULL
GROUP BY department_id
ORDER BY sal_sum DESC;
--多个分组表达式
SELECT department_id,job_id,SUM(SALARY)
FROM   employees
GROUP BY department_id,job_id;

 

--查询每个部门的部门名称,人数:

SELECT d.department_name,count(e.employee_id) emp_count
FROM   employees e
INNER JOIN departments d ON e.department_id=d.department_id
GROUP BY d.department_name;

--统计每年入职的人数:年份,人数

SELECT to_char(hire_date,'yyyy') 年份,count(*) 人数
FROM  employees
GROUP BY to_char(hire_date,'yyyy')
ORDER BY 1;

 非法使用组函数:

  • 不能在where子句中使用组函数
  • 可以在having子句中使用组函数

--查询部门编号,每个部门的平均共组,平均工资大于8000的

 

select department_id, avg(salary) from employees group by department_id having avg(salary)>8000 and department_id is not null;

--统计每年入职的人数:年份,人数(仅返回入职不少于2人的年份的数据)

select to_char(hire_date,'yyyy'),count(*)
from employees
group by to_char(hire_date,'yyyy')
having count(*)>=2;  


--WHERE条件:过滤分组之前的数据
--HAVING条件:过滤分组之后的数据  

--查询每个部门的ID,员工工资总和(where 可以存放在 分组之前)

select department_id,sum(salary)
from employees
group by department_id
having department_id is not null;  

子查询:

 

--查询谁的工资比Abel高?(先查询Abel的工资,再去查询比他高的值)

select salary from employees where last_name='Abel';

  

select * from employees where salary>(select salary from employees where last_name='Abel');

--查询工资最低的员工(先查询最低工资为多少,在查询最低工资的员工)

select min(salary) from employees;  

SELECT *
FROM   employees
WHERE  salary = (SELECT MIN(salary)
                 FROM   employees);

--查询和149号员工同一个部门的其他员工

  •  先去查询149号员工所在的部门编号:
SELECT department_id
                        FROM   employees
                        WHERE  employee_id = 149

 

  •   再查询80号员工部门的员工出过149号员工
SELECT *
FROM   employees
WHERE  department_id = (SELECT department_id
                        FROM   employees
                        WHERE  employee_id = 149)
AND    employee_id <> 149;

--查询比202号员工的部门经理的工资还要高的员工

  • 查询202号员工所在的部门编号(20号部门)
  • 查询20号部门的员工经理id(201号)
  • 查询经理的工资
  • 查询还要高的员工
SELECT *
FROM   employees
WHERE  salary > (SELECT salary
                 FROM   employees
                 WHERE  employee_id =
                        (SELECT manager_id
                         FROM   departments
                         WHERE  department_id =
                                (SELECT department_id
                                 FROM   employees
                                 WHERE  employee_id = 202)));

--查询员工编号,姓名,工资,工资总和(在查询列表中使用子查询,只能是单行单列) 

SELECT employee_id,last_name,salary,
       (SELECT SUM(salary) FROM employees) AS 工资总和
FROM   employees;

--查询工资最高的前5名的员工(临时视图,内联视图)

SELECT *
FROM   (SELECT *
        FROM   employees
        ORDER  BY salary DESC)
WHERE  ROWNUM <= 5;

--查询员工表中第6到第12条数据

SELECT *
FROM   (SELECT ROWNUM rnum,
               e.*
        FROM   employees e)
WHERE  rnum BETWEEN 6 AND 12;

--推荐以下写法,效率较高

SELECT *
FROM   (SELECT ROWNUM rnum,
               e.*
        FROM   employees e
        WHERE  ROWNUM <= 12)
WHERE  rnum >= 6;

 
--查询工资最高的第6到第12条员工 

SELECT *
FROM   (SELECT rownum rnum,
               e.*
        FROM   (SELECT *
                FROM   employees
                ORDER  BY salary DESC) e
        WHERE  rownum <= 12)
WHERE  rnum >= 6;

--查询所有是部门经理的员工(多行子查询)

SELECT *
FROM   employees
WHERE  employee_id IN (SELECT manager_id
                       FROM   departments);

--查询所有不是部门经理的员工(多行子查询)

SELECT *
FROM   employees
WHERE  employee_id NOT IN
       (SELECT manager_id
        FROM   departments
        WHERE  manager_id IS NOT NULL);

--ANY逻辑或比较  >ANY(50,80,90)

--查询大于60号部门任何一个员工工资的员工

SELECT *
FROM   employees
WHERE  salary > ANY (SELECT salary
        FROM   employees
        WHERE  department_id = 60);

 
--ALL逻辑与比较  >ALL(50,80,90) 

 --查询所有员工人数不少于3人的部门信息

SELECT *
FROM   departments
WHERE  department_id IN (SELECT department_id
                         FROM   employees
                         GROUP  BY department_id
                         HAVING COUNT(*) >= 3);

 

 

 

  

  

 

  

  

  

  

  

  

  

 

 

 

 

posted @ 2018-10-25 17:48  少侠gqk  阅读(1450)  评论(0编辑  收藏  举报