Java中将xml转为List<实体类>
我是一个IT新人,刚进入公司遇到了将Xml转为List<实体类>的情况,网上搜了一些资料,最后终于搞定,在这里分享一下
第一步:给出一个实体类C47
public class C47 { private String code; private String message; private String rownum; private String jylsh; //检验流水号 varchar2 private String jyjgbh; // 检验机构编号 varchar2 private String hphm; // 号牌号码 varchar2 private String hpzl; // 号牌种类 varchar2 private String wgjyzp; // 外观检验照片 varchar2 private String zlzp; // 资料照片 varchar2 private String wgjcxm; // 外观检验项目 varchar2 private String dtdpjyxm; // 底盘动态检验项目 varchar2 private String dpjyxm; // 底盘检验项目 varchar2 private String pdyj; // 判定依据 char private String yqsbjyxm; // 仪器设备检验项目 varchar2 }
第二步:将Xml转换为map放到List容器里面
public static List<Map<String, Object>> xmlToMap(String result) throws IOException, SAXException, ParserConfigurationException { DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); DocumentBuilder db = dbf.newDocumentBuilder(); Document doc = db.parse(new InputSource(new ByteArrayInputStream(result.getBytes("GBK")))); NodeList bookList = doc.getElementsByTagName("vehispara"); List<Map<String, Object>> list = new ArrayList(); for (int i = 0; i < bookList.getLength(); i++) { Node book = bookList.item(i); NamedNodeMap attrs = book.getAttributes(); for (int j = 0; j < attrs.getLength(); j++) { Node attr = attrs.item(j); } NodeList childNodes = book.getChildNodes(); Map<String, Object> map = new HashMap(); for (int k = 0; k < childNodes.getLength(); k++) { String Code = doc.getElementsByTagName("code").item(0).getChildNodes().item(0).getNodeValue(); String Message = doc.getElementsByTagName("message").item(0).getChildNodes().item(0).getNodeValue(); String Rownum = doc.getElementsByTagName("rownum").item(0).getChildNodes().item(0).getNodeValue(); map.put("code", Code); map.put("message", Message); map.put("rownum", Rownum); //组织成某种格式 传回去然后 再转成entity if (childNodes.item(k).getNodeType() == Node.ELEMENT_NODE) { String name = childNodes.item(k).getNodeName(); String value = childNodes.item(k).getTextContent(); //set key,value map.put(name, value); } } list.add(map); } return list; }
第三步:将第二步中返回的map转换为实体类
public static Object transMap2Bean(Map<String, Object> map, Object obj) { try { BeanInfo beanInfo = Introspector.getBeanInfo(obj.getClass()); PropertyDescriptor[] propertyDescriptors = beanInfo.getPropertyDescriptors(); for (PropertyDescriptor property : propertyDescriptors) { String key = property.getName(); if (map.containsKey(key)) { Object value = map.get(key); // 得到property对应的setter方法 Method setter = property.getWriteMethod(); setter.invoke(obj, value); } } } catch (Exception e) { } return obj; }
第三步: 遍历第一步返回的List,转换为实体类存放到List里面
public static List<Object> getBeans(List<Map<String, Object>> list,Class<?> clazz) { Object obj1 = null; List<Object> list1 = new ArrayList<Object>(); for (int i = 0; i < list.size(); i++) { Map<String, Object> stringObjectMap = list.get(i); Object obj =null; try { obj=clazz.newInstance(); } catch (InstantiationException e) { e.printStackTrace(); } catch (IllegalAccessException e) { e.printStackTrace(); } obj1 = transMap2Bean(stringObjectMap, obj); list1.add(obj1); } return list1; }
方法已经完成,接下来我们测试一下哦
public static void main(String[] args) throws Exception { //给出的Xml的String型 String s = "<?xml version=\"1.0\" encoding=\"GBK\"?>\n" + "<root>\n" + "<head>\n" + "<code>1</code>\n" + "<message>数据下载成功！</message>\n" + "<rownum>1</rownum>\n" + "</head>\n" + "<body>\n" + "<vehispara id=\"0\">\n" + " <dtdpjyxm></dtdpjyxm>\n" + " <pdyj>2</pdyj>\n" + " <zlzp>0201,0202,0203,0204,0205,0206,0211,0209,0212,0213</zlzp>\n" + " <yqsbjyxm>B1,B2,H1,H2,H3,H4</yqsbjyxm>\n" + " <cyxm></cyxm>\n" + " <cyzp>0111,0112,0113,0119,0115,0171,0174</cyzp>\n" + " <hphm></hphm>\n" + " <dpjyxm></dpjyxm>\n" + " <jyjgbh>3703000017</jyjgbh>\n" + " <jylsh>我是1</jylsh>\n" + " <wgjyzp>0111,0112,0113,0119,0115,0171,0174</wgjyzp>\n" + " <hpzl>02</hpzl>\n" + " <wgjcxm>01,02,03,04,05,09,16,17,18,19,20,21,22,23,80</wgjcxm>\n" + "</vehispara>\n" + "<vehispara id=\"1\">\n" + " <dtdpjyxm></dtdpjyxm>\n" + " <pdyj>2</pdyj>\n" + " <zlzp>0201,0202,0203,0204,0205,0206,0211,0209,0212,0213</zlzp>\n" + " <yqsbjyxm>B1,B2,H1,H2,H3,H4</yqsbjyxm>\n" + " <cyxm></cyxm>\n" + " <cyzp>0111,0112,0113,0119,0115,0171,0174</cyzp>\n" + " <hphm>鲁CZ513M</hphm>\n" + " <dpjyxm></dpjyxm>\n" + " <jyjgbh>3703000017</jyjgbh>\n" + " <jylsh>你是2</jylsh>\n" + " <wgjyzp>0111,0112,0113,0119,0115,0171,0174</wgjyzp>\n" + " <hpzl>02</hpzl>\n" + " <wgjcxm>01,02,03,04,05,09,16,17,18,19,20,21,22,23,80</wgjcxm>\n" + "</vehispara>\n" + "</body>\n" + "</root>"; //TreeUtil是上面三个方法的实体类 List<Map<String, Object>> list = TreeUtil.xmlToMap(s); //C47是我们要转换成的实体类 List<Object> beans = TreeUtil.getBeans(TreeUtil.xmlToMap(s),C47.class); //我们遍历看一下结果哦 for (int i = 0; i < beans.size(); i++) { System.out.println("结果是" + i + " " + beans.get(i)); }
是不是很期待结果哦
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结果是0 C47{code='1', message='数据下载成功！', rownum='1', jylsh='我是1', jyjgbh='3703000017', hphm='', hpzl='02', wgjyzp='0111,0112,0113,0119,0115,0171,0174', zlzp='0201,0202,0203,0204,0205,0206,0211,0209,0212,0213', wgjcxm='01,02,03,04,05,09,16,17,18,19,20,21,22,23,80', dtdpjyxm='', dpjyxm='', pdyj='2', yqsbjyxm='B1,B2,H1,H2,H3,H4'}
结果是1 C47{code='1', message='数据下载成功！', rownum='1', jylsh='你是2', jyjgbh='3703000017', hphm='鲁CZ513M', hpzl='02', wgjyzp='0111,0112,0113,0119,0115,0171,0174', zlzp='0201,0202,0203,0204,0205,0206,0211,0209,0212,0213', wgjcxm='01,02,03,04,05,09,16,17,18,19,20,21,22,23,80', dtdpjyxm='', dpjyxm='', pdyj='2', yqsbjyxm='B1,B2,H1,H2,H3,H4'}
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结果正如我们期待的,但是有一个局限性就是:返回的实体类的字段属性只是String类型,大家使用的时候一定要注意哦!
有没有好的解决方法,求帮忙!!!!!!!
关于上面的局限性问题,我已经解决, 大家可以参考这个链接 : https://www.cnblogs.com/514929hgy/p/9143182.html
希望可以帮助大家!!!!!!
