F - 数论

Description

There is a hill with n holes around. The holes are signed from 0 to n-1.



A rabbit must hide in one of the holes. A wolf searches the rabbit in anticlockwise order. The first hole he get into is the one signed with 0. Then he will get into the hole every m holes. For example, m=2 and n=6, the wolf will get into the holes which are signed 0,2,4,0. If the rabbit hides in the hole which signed 1,3 or 5, she will survive. So we call these holes the safe holes.

Input

The input starts with a positive integer P which indicates the number of test cases. Then on the following P lines,each line consists 2 positive integer m and n(0<m,n<2147483648).

Output

For each input m n, if safe holes exist, you should output "YES", else output "NO" in a single line.

Sample Input

2
1 2
2 2

Sample Output

NO
YES


题目大意：有0到n-1个洞，狼从0开始找，然后隔m个依次往右寻找，n为小白兔所在的位置，现在让我们判断小白兔是否安全。
就是求最大公约数。有方向就好办了。

代码如下：
#include<cstdio>
int main()
{
   long long m,n,t,temp;
    scanf("%d",&t);
     while(t--)
     {
          scanf("%lld%lld",&m,&n);
          while(n!=0)
          {
               temp=n;
               n=m%n;
               m=temp;
          }
     if(m==1)printf("NO\n");
     else printf("YES\n");
     }
     return 0;
}