hdu 1671 Phone List Trie 基础模板
Phone List
Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 6134 Accepted Submission(s): 2085
Problem Description
Given a list of phone numbers, determine if it is consistent in the sense that no number is the prefix of another. Let’s say the phone catalogue listed these numbers:
1. Emergency 911
2. Alice 97 625 999
3. Bob 91 12 54 26
In this case, it’s not possible to call Bob, because the central would direct your call to the emergency line as soon as you had dialled the first three digits of Bob’s phone number. So this list would not be consistent.
1. Emergency 911
2. Alice 97 625 999
3. Bob 91 12 54 26
In this case, it’s not possible to call Bob, because the central would direct your call to the emergency line as soon as you had dialled the first three digits of Bob’s phone number. So this list would not be consistent.
Input
The first line of input gives a single integer, 1 <= t <= 40, the number of test cases. Each test case starts with n, the number of phone numbers, on a separate line, 1 <= n <= 10000. Then follows n lines with one unique phone number on each line. A phone number is a sequence of at most ten digits.
Output
For each test case, output “YES” if the list is consistent, or “NO” otherwise.
Sample Input
2 3 911 97625999 91125426 5 113 12340 123440 12345 98346
Sample Output
NO YES
Source
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// Trie 基础模板
#include <stdio.h> #include <string.h> #include <algorithm> #include <vector> #include <stack> #include <iostream> #define Max 100000 #define sigma_size 10 using namespace std; int ch[Max][sigma_size]; bool val[Max]; int cnt; char str[10002]; int idx(char c) { return c-'0'; } bool insert(char *s) { int i,n=strlen(s); int c,u=0; for(i=0;i<n;i++) { c=idx(s[i]); if(!ch[u][c]) { memset(ch[cnt],0,sizeof(ch[cnt])); val[cnt]=false; ch[u][c]=cnt++; } if(val[u]) return false; u=ch[u][c]; } val[u]=true; for(i=0;i<sigma_size;i++) //做题时开始忘记这、错了下 if(ch[u][i]) return false; return true; } int main() { int T; int n,i; scanf("%d",&T); bool flag; while(T--) { flag=true; val[0]=0; memset(ch[0],0,sizeof(ch[0])); cnt=1; scanf("%d",&n); for(i=0;i<n;i++) { scanf("%s",str); if(!insert(str)) flag=false; } if(flag) printf("YES\n"); else printf("NO\n"); } return 0; }