hdu 4079 Happy Telephones
Happy Telephones
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 199 Accepted Submission(s): 159
Problem Description
In the land of Eden, all phone conversations are happy ones. People complaining on the phone are immediately put in jail. To enforce this law, the police taps all phone conversations.
The police wants to hire the approriate number of operators to listen to all conversations in a given period of time. Unfortunately, each of their operators can listen to one conversation only before needing a really long break to rest from the effort.
As a contractor of the police department, you have been asked to provide a program capable of determining the required number of operators. If the program does not work correctly, you will be put in jail as well, along with all the unhappy complainers. Do you really want to end up there?
![](http://acm.hdu.edu.cn/data/images/C297-1009-1.jpg)
The police wants to hire the approriate number of operators to listen to all conversations in a given period of time. Unfortunately, each of their operators can listen to one conversation only before needing a really long break to rest from the effort.
As a contractor of the police department, you have been asked to provide a program capable of determining the required number of operators. If the program does not work correctly, you will be put in jail as well, along with all the unhappy complainers. Do you really want to end up there?
![](http://acm.hdu.edu.cn/data/images/C297-1009-1.jpg)
Input
Each test case starts with two integers denoting the number of phone calls N (1 <= N < 10 000) and the number of intervals M (1 <= M < 100). This is followed by N lines describing the telephone calls, each one consisting of four integers Source, Destination, Start and Duration. Source and Destination identify the pair of telephone numbers establishing the connection (0 <= Source, Destination <= 10 000 000). Start and Duration are the start time and duration of the call in seconds (1 <= Duration <= 10 000 and Start >= 0). You can safely assume that the sum of Start and Duration fits into a 32-bit signed integer.
Afterwards follow M lines containing the time intervals the police are interested in, each on described by two integers Start and Duration, in the same format and with the same meaning and constraints as those in the telephone calls. The last test case is represented by N = M = 0 and must not be processed.
Afterwards follow M lines containing the time intervals the police are interested in, each on described by two integers Start and Duration, in the same format and with the same meaning and constraints as those in the telephone calls. The last test case is represented by N = M = 0 and must not be processed.
Output
For each of the M intervals of each test case, print the number of calls that are active during at least one second of the interval.
Sample Input
3 2
3 4 2 5
1 2 0 10
6 5 5 8
0 6
8 2
1 2
8 9 0 10
9 1
10 1
0 0
Sample Output
3
2
1
0
Source
Recommend
lcy
//很简单的一题、我一开始就想复杂了
//居然用上了线段树、离散化、、、还是错的方法
//其实只要判断2条线段有没有交点
//看到别人提交代码那么短、醒悟过来、、
#include <iostream> #include <stdio.h> #include <string.h> #include <algorithm> #include <queue> #include <cmath> #define N 10002 using namespace std; struct node { int x,y; }st[N]; int main() { int i,j,k; int n,m; int s,d,f,t; while(scanf("%d%d",&n,&m),n||m) { for(i=0;i<n;i++) { scanf("%d%d",&s,&d); scanf("%d%d",&f,&t); st[i].x=f;st[i].y=f+t; } for(i=0;i<m;i++) { scanf("%d%d",&f,&t);t=f+t; for(k=0,j=0;j<n;j++) { if(st[j].y>f&&st[j].x<t) k++; } printf("%d\n",k); } } return 0; }