数据转换-位串字节数组

0. 在openEuler(推荐)或Ubuntu或Windows(不推荐)中完成下面任务

1 参考《GMT 0009-2012 SM2密码算法使用规范》第6节“数据转换” 在utils.h和utils.c中完成位串与８位字节串的转换功能(10')：
int Bitstr2ByteArr(unsigned char * bs, unsigned char * ba，int *lba);
int ByteArr2Bitstr(unsigned char * ba, unsigned char * bs, int *lbs);

2 并写出测试代码测试上述函数(不能与下面代码一样)，比如(10'):

unsigned char bs [] = "1010010100011100";
int len;
Bitstr2ByteArr(bs, char * ba, &len);
//结果：ba = {0x5, 0x1C}; len=2

char ba[] = {0x5, 0x1C}
ByteArr2Bitstr(char * ba, char * bs);
//结果：bs= "1010010100011100"
3 提交代码（或代码链接）和运行结果

mian.c

#include <stdio.h>
#include "utils.h"
void main(){
char ba1[] = "1325";
char bs1[] = "1100110000110100";
char bs2[100];
char ba2[100];
ByteArr2Bitstr(ba1,bs2);
}

utils.c

#include <stdio.h>
#include <string.h>
#include "utils.h"

char Hex2Char(int i){

if(i>=0 && i<= 9)
return i + 0x30;
// return i + '0'
if(i>=10 && i<=15)
return i + 0x37;
//return i + 'A' - 10;

}
int Char2Hex(char x){
if(x>48&&x<58)
return x-48;
if(x>65&&x<75)
return x - 55;
}
void B2Arr(char bs[],char ba[])

{
printf("1");
int b1,b2,b3,b4,b5,i;
for(i = 0;i<strlen(bs);i+4)
{b1 = Char2Hex(bs[i]);
b2 = Char2Hex(bs[i + 1]);
b3 = Char2Hex(bs[i+2]);
b4 = Char2Hex(bs[i + 3]);
b5 = b1*8 + b2*4 + b3*2 + b4*1;
ba[i/4] = Hex2Char(b5);
}
printf("%s转化为%s\n",bs,ba);
return 0;
}
void ByteArr2Bitstr(char ba[],char bs[], int *lba)
{
int b1,b2,b3,b4,b5,i;
for (i = 0;i<strlen(ba);i++)

{b5 = Char2Hex(ba[i]);
b1 = b5/8;
b2 = (b5-b1*8)/4;

b3 = (b5-b1*8 -b2*4)/2;

b4 = b5%2;

bs[i*4] = Hex2Char(b1);
bs[i*4+1] = Hex2Char(b2);
bs[i*4+2] = Hex2Char(b3);
bs[i*4+3] = Hex2Char(b4);
}
printf("%s转化为%s\n",ba,bs);

}

utils.h

#ifndef  _UTILS_H_
#define  _UTILS_H_

int ByteArr2Bitstr(int ba[],int bs[],int *lba); 

int Bitstr2ByteArr(int bs[],int ba[],int *lbs); 

#endif

运行结果