Day 14 作业

info_list = []

with open('info.txt', 'r', encoding='utf8') as fr:
    for info in fr:
        info_dict = {}
        name, sex, age, salary = info.strip().split()

        info_dict['name'] = name
        info_dict['sex'] = sex
        info_dict['age'] = int(age)
        info_dict['salary'] = int(salary)
        # print(info_dict)
        info_list.append(info_dict)
print(info_list)

# 根据1得到的列表，取出薪资最高的人的信息
print(max(info_list, key=lambda dic: dic['salary']))

# 根据1得到的列表，取出最年轻的人的信息
print(min(info_list, key=lambda dic: dic['age']))

# 根据1得到的列表，将每个人的信息中的名字映射成首字母大写的形式
res = map(lambda dic: dic['name'].capitalize(), info_list)
print(list(res))

# 根据1得到的列表，过滤掉名字以a开头的人的信息
res = filter(lambda dic: dic['name'][0] != 'a', info_list)
print(list(res))

# 使用递归打印斐波那契数列(前两个数的和得到第三个数，如：0 1 1 2 3 4 7...)
n1 = 0
n2 = 1
count = 0
def a(x):
    global count
    global n1
    global n2
    if x == 1:
        print(n1)
    elif x == 2:
        print(n1, n2)
    else:
        while count < x:
            nsum = n1 + n2
            print(nsum, end=',')
            n1 = n2
            n2 = nsum
            count += 1
            a(x)

a(10)

# 一个嵌套很多层的列表，如l=［1,2,[3,[4,5,6,[7,8,[9,10,[11,12,13,[14,15]]]]]]］，用递归取出所有的值

# x = 0
l = [1,2,[3,[4,6,[7,8,[9,10,[11],[12,[13,14],[15]]]]]]]
# n = len(l)
# def lis(l):
#     # global x
#     print(l[0])
#
#     l.remove(l[0])
#     if type(l[0]) == list:
#         l = l[0]
#     # l = l[0]
#
#     lis(l)

# lis(l)

def lis(l):
    for i in l:
        if type(i) == list:
            lis(i)
        else:
            print(i)

lis(l)