js 回文数

getreverNum(num){
                console.log('num----------'+num)
                let numStr = num.toString();
                let numStrRever = numStr.split('').reverse().join('')
                console.log('numStrRever----'+numStrRever)
                let preZeroNum = 0 ;
                for(let i = 0 ;i<numStrRever.length;i++){
                    let item = numStrRever.substr(i,1);
                    if((item==0)&&(i-preZeroNum==0)){
                        preZeroNum ++ ;
                    }
                }
                let reverNum = numStrRever;
                if(preZeroNum>0){
                    reverNum = numStrRever.substr(preZeroNum,numStrRever.length-preZeroNum)
                }                 
                console.log('reverNum----'+parseInt(reverNum))
                return  parseInt(reverNum)  ;
            },

 

调用检验：

let num = that.getreverNum(1234) ;
            num = that.getreverNum(12345) ;
            num = that.getreverNum(126000) ;
            num = that.getreverNum(12700) ;
            num = that.getreverNum(123401) ;
            num = that.getreverNum(123401) ;