1082 Read Number in Chinese (25分)

注意事项：

八千万八千（√），八千万零八千（×）

输入为0时单独判断

#include <iostream>
#include <cstring>
using namespace std;
int main()
{
    char out_num[10][5] = { "yi","er","san","si","wu","liu","qi","ba","jiu" };
    char out[3][7] = { " Shi"," Bai"," Qian" };
    char N[11];
    bool first = true;
    bool print_zero = true;//Wan与Qian
    cin >> N;
    if (N[0] == '-')
    {
        cout << "Fu";
        first = false;
        for (int i = 0; i < strlen(N); ++i)
        {
            N[i] = N[i + 1];
        }
    }
    int len = strlen(N);
    int zero = 0;//是否积累“零”
    int dif;
    for (int i = 0; i < len; ++i)
    {
        dif = len - i;
        if (dif < 5)
        {
            if (N[i] != '0')
            {
                if (zero == 1)
                {
                    cout << " ling";
                    zero = 0;
                }
                if (!first)cout << " ";
                first = false;
                cout << out_num[N[i] - '0' - 1];
                if (dif >= 2)
                    cout << out[dif - 2];
            }
            else
            {
                if (i == 0)
                {
                    cout << "ling";
                    return 0;
                }
                zero = 1;
            }
        }
        else if (dif == 5)
        {

            if (N[i] != '0')
            {
                if (zero == 1)
                {
                    cout << " ling";
                    zero = 0;
                }
                if (!first)cout << " ";
                first = false;
                cout << out_num[N[i] - '0' - 1];
            }
            if (!(N[len - 6] == '0' && N[len - 7] == '0' && N[len - 8] == '0'))
            {
                cout << " Wan";
                zero = 0;
            }

        }
        else if (dif > 5 && dif < 9)
        {
            if (N[i] != '0')
            {
                zero = 0;
                if (!first)cout << " ";
                first = false;
                cout << out_num[N[i] - '0' - 1];
                if ((dif + 2) % 4 >= 0)
                    cout << out[(dif + 2) % 4];
            }
            else
            {
                zero = 1;
            }
        }
        else if (dif == 9)
        {
            if (!first)cout << " ";
            first = false;
            cout << out_num[N[i] - '0' - 1] << " Yi";
        }
    }
    return 0;
}