1077 Kuchiguse (20分)——测试点1未过

#include <iostream>
#include <cstring>
using namespace std;
int main()
{
    int N;
    cin >> N;
    char ch;
    int k = -1;
    char(*s)[300] = new char[101][300];
    int len[101] = { 0 };
    cin.get();//接收换行符
    for (int i = 0; i < N; ++i)
    {
        int t = 0;
        while (ch = cin.get())
        {
            if (ch == '\n')break;
            s[i][t++] = ch;
        }
        s[i][t] = '\0';
        len[i] = strlen(s[i]);
    }
    int finish = 0;
    for (int j = 0; j <= len[0] && !finish; ++j)//考虑整个字符串作为后缀,<=len[0]
        for (int i = 1; i < N && !finish; ++i)
        {
            int temp = len[i] - 1 - j;
            if (temp < 0 || (s[i][temp] != s[0][len[0] - 1 - j]))
            {
                k = j;
                finish = 1;
            }
        }
    if (!k)
    {
        cout << "tai";
    }
    else 
    {
        for(int i=len[0]-k; i<len[0]; ++i)
        {
            cout << s[0][i];
        }
    }
    return 0;
}

 

posted @ 2020-09-29 09:25  幻想Elapse  阅读(130)  评论(0编辑  收藏  举报