数据转换-位串字节数组

任务详情

0. 在openEuler(推荐)或Ubuntu或Windows(不推荐)中完成下面任务
1. 参考《GMT 0009-2012 SM2密码算法使用规范》第6节“数据转换” 在附件中的utils.h和utils.c中完成位串与８位字节串的转换功能(10')：

int Bitstr2ByteArr(unsigned char * bs, unsigned char * ba，int *lba);
int ByteArr2Bitstr(unsigned char * ba, unsigned char * bs, int *lbs);

2. 并写出测试代码测试上述函数(不能与下面代码一样)，比如(10'):

unsigned char bs [] = "1010010100011100";
int len;
Bitstr2ByteArr(bs, char * ba, &len);
//结果：ba = “051C”; len=2
char ba[] = "051C";
ByteArr2Bitstr(char * ba, char * bs);
//结果：bs= "1010010100011100"

3. 提交代码（或代码链接）和运行结果

代码

main.c

#include"utils.h"
#include<string.h>
#include<stdio.h>
//20201212
int main() {
	char ba[100];
	char bs[100];
	printf("input ByteArr:\n");
	scanf("%s",ba);
	ByteArr2Bitstr(ba,bs);
	printf("bitstr:\n");
	printf("%s\n",bs);

	char baa[100];
	char bss[100];
	printf("input bitstr:\n");
	scanf("%s",bss);
	Bitstr2ByteArr(bss,baa);
	printf("ByteArr:\n");
	printf("%s\n",baa);
	int a = strlen(baa);
	printf("len = %d\n",a/2);
	return 0;
}

utils.c

#include<stdio.h>
#include<string.h>
#include"utils.h"

int Hex2Char(int fromi,char *toc) {
	if(fromi>=0&&fromi<=9) {
		*toc= fromi+'0';
	} else if(fromi>=10&&fromi<=15) {
		*toc = fromi+'A'-10;
	} else {
		printf("error");
	}
	return 0;
}
int Char2Hex(char fromc,int *toi) {
	if(fromc>='0'&& fromc<='9') {
		*toi= fromc-'0';
	} else if(fromc>='A'&& fromc<='F') {
		*toi= fromc-'A'+10;

	} else {
		printf("error");
	}
	return 0;
}
int ByteArr2Bitstr(char *ba,char *bs) {
	int i,j,L,k,a;
	L = strlen(ba);
	for(j=0; j<L; j++) {
		Char2Hex(ba[j],&a);
		for(i=0; i<4; i++) {
			bs[3*(j+1)-i+j] = a%2+'0';
			a=a/2;
		}
	}
	bs[4*L]='\0';
}
int Bitstr2ByteArr(char *bs,char *ba) {
	int i,k,j,L;
	L = strlen(bs);
	char string[100];
	int sum=0;
	if(L%4==1) {
		strcpy(string,"000");
		strcat(string,bs);
		k=L/4+1;
	} else if(L%4==2) {
		strcpy(string,"00");
		strcat(string,bs);
		k=L/4+1;
	} else if(L%4==3) {
		strcpy(string,"0");;
		strcat(string,bs);
		k=L/4+1;
	} else {
		k=L/4;
		strcpy(string,bs);
	}
	for(i=0; i<k; i++) {
		for(j=0; j<4; j++) {
			sum=sum*2;
			sum=sum+(string[4*i+j]-'0');
		}
		Hex2Char(sum,&ba[i]);
		sum=0;
	}
	ba[i]='\0';
}

utils.h

#ifndef _UTIL_H_
#define _UTIL_H_

//char Hex2Char(int i);
//int Char2Hex(char c);

int Hex2Char(int fromi,char * toc);
int Char2Hex(char fromc,int * toi);

int Bitstr2ByteArr(char * bs,char * ba);
int ByteArr2Bitstr(char * ba,char * bs);

int Int2ByteArr(int i,char * ba);
int ByteArr2Int(char * ba,int * i);

#endif

运行