向量 vector

#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
bool cmp(int a,int b)
{    return a>b;  }

int main()
{ 
    int n,i;
    cin>>n;
    vector<int> a(n);
    for(i=0;i<n;i++)
                      {         cin>>a[i];    }
    
    sort(a.begin(),a.end(),cmp);
    
    cout<<endl;
    for(i=0;i<n;i++)
                      {  cout<<a[i]<<"    ";    }
    cout<<endl;
    return 0;
}

#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
bool cmp(int a,int b)
{ return a>b; }

int main()
{
int n,i;
cin>>n;
vector<int> a(n);
for(i=0;i<n;i++)
{ cin>>a[i]; }

sort(a.begin(),a.end(),cmp);

cout<<endl;
for(i=0;i<n;i++)
{ cout<<a[i]<<" "; }
cout<<endl;
return 0;
}

 

 

 

 

 

 

 

#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
int main()
{
    int i=0;
    vector<string> s_word(100),s_word1;
    string word,word1;
    while(cin>>word)
    {
        s_word[i++]=word;
        s_word1.push_back(word);
    }

    for(int i=0;i<s_word.size();i++)
    {
        cout<<s_word[i]<<" ";
    }
    
    cout<<endl;
    cout<<"单词个数为："<<s_word.size()<<endl<<endl;
    cout<<"去掉重复单词后："<<endl;
    
    //去年重复的单词
    s_word.erase(unique(s_word.begin(),s_word.end()),s_word.end());
    
    for(int i=0;i<s_word.size();i++)
    {
        cout<<s_word[i]<<" ";
    }
    cout<<endl;
    cout<<"单词个数为："<<s_word.size()<<endl;
    
    //每个单词有原来的文章中所占的比率
    cout<<"每个单词的频率："<<endl; 
    for(int i=0;i<s_word.size();i++)
    {
        //cout<<s_word[i]<<":  "<<(double)count(s_word1.begin(),s_word1.end(),s_word[i])/s_word1.size()<<endl;
    }
    
}

 

 

 

 

 

 

#include<iostream>
#include<vector>
#include<algorithm>
using namespace std;
struct f
{   int x;
    int y;
    double r;
}a[100000];
int f1(int fz,int fm)
{    return fm==0?fz:f1(fm,fz%fm);}
bool cmp(struct f a1,struct f a2)
{
    return a1.r<a2.r;
}
int main()
{
    int n,i,j,k=0,t;
    cin>>n;
    for(i=1;i<n;i++)
        for(j=i+1;j<=n;j++)
          if(f1(i,j)==1) 
          {    a[k].x=i;a[k].y=j;a[k].r=(double)i/j; k++;}
    cout<<0<<'/'<<1<<endl;        
    sort(a,a+k,cmp);
    for(i=0;i<k;i++)
        cout<<a[i].x<<'/'<<a[i].y<<endl;
    cout<<1<<'/'<<1<<endl;
    return 0;
}