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摘要: #include#includeint main(void){ int i,n,sum; printf("Enter n:"); scanf("%d",&n); sum=0; for(i=1;i<=n;i++){ sum=sum+pow(2,i); } printf("result=%d\n",sum); return 0;} 阅读全文
posted @ 2013-10-21 09:49 dihuanting 阅读(109) 评论(1) 推荐(0) 编辑
摘要: #include#includeint main(){ int m,y; double rate,money,loan; double s(double rate,double loan,int m); printf("Enter loan,rate:"); scanf("%lf%lf",&loan,&rate); for(y=5;y<=30;y++){ m=12*y; money=s(rate,loan,m); printf("年分%d 月还款额%.1f\n",y,money); } ... 阅读全文
posted @ 2013-10-21 09:37 dihuanting 阅读(117) 评论(0) 推荐(0) 编辑
摘要: #includeint main(void){ int i,n; double item,sum,flag; flag =1; sum =0; printf("Enter n:"); scanf("%d",&n); for(i=1;i<=n;i++){ item=(flag*i)/(2*i-1); flag=-flag; sum=sum+item; } printf("sum=%f\n",sum); } 阅读全文
posted @ 2013-10-21 09:24 dihuanting 阅读(149) 评论(0) 推荐(0) 编辑
摘要: #includeint main(void){ int m,n,i; double y; y=0; printf("Entern,m:"); scanf("%d%d",&m,&n); for(i=m;i<=n;i++) y=y+(i*i+1.0/i); printf("y=%Lf\n",y); } 阅读全文
posted @ 2013-10-21 09:15 dihuanting 阅读(103) 评论(0) 推荐(0) 编辑
摘要: #includeint main(void){ int i,n; double x,sum; printf("Enter x,n:"); scanf("%lf%d",&x,&n); sum=1; for(i=1;i<=n;i++){ sum=sum*x; } printf("x^n=%.2f\n",sum); return 0;} 阅读全文
posted @ 2013-10-20 17:32 dihuanting 阅读(116) 评论(0) 推荐(0) 编辑
摘要: #includeint main(void){ int i,n; double x,sum; printf("Enter x,n:"); scanf("%lf%d",&x,&n); sum=1; for(i=1;iint main(void){ double num1,num2; char op; printf("Type in an expression:"); scanf("%lf%c%lf",&num1,&op,&num2); if(op=='+') p 阅读全文
posted @ 2013-10-20 15:20 dihuanting 阅读(197) 评论(1) 推荐(0) 编辑
摘要: #include int main(void) { int i,n; double x; double fact(int n); scanf ("%d", &n); x=0; for(i=0;i<=n;i++){ x=x+fact(i); } printf("x=%.0f\n",x); return 0;}double fact(int n) { int i; double y; y=1; for(i=1;i<=n;i++){ y=y*i; } return y; } 阅读全文
posted @ 2013-10-19 22:41 dihuanting 阅读(94) 评论(1) 推荐(0) 编辑
摘要: #includeint main(void){ double r,h,v; printf("Enter r,h:"); scanf("%lf%lf",&r,&h); if(r<0,h<0){ printf("sorry you enter is wrony!\n"); } else{ v=3.1415926*r*r*h; printf("%.3f\n",v);} } 阅读全文
posted @ 2013-10-19 22:23 dihuanting 阅读(148) 评论(1) 推荐(0) 编辑
摘要: #includeint main(void){ int i,n; double r,h,v; printf("Enter n:"); scanf("%d",&n); for(i=1;i<=n;i++){ printf("Enter r,h:"); scanf("%Lf%Lf",&r,&h); if(r<0,h<0) printf("输入错误,请重新输入"); else v=3.14159*r*r*h; printf("%.3f\n", 阅读全文
posted @ 2013-10-17 09:44 dihuanting 阅读(123) 评论(0) 推荐(0) 编辑
摘要: #includeint main(void){double R,S; printf("Enter R:\n");scanf("%Lf",&R);if(R<=0)printf("sorry your enter is wrong!\n");else{S=3.1415926*R*R;printf("%.2f",S);}return 0;} 阅读全文
posted @ 2013-10-14 09:33 dihuanting 阅读(147) 评论(0) 推荐(0) 编辑
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