摘要: exec1#include #include int main(){ char *arglist[3]; arglist[0] = "ls"; arglist[1] = "-l"; arglist[2] = 0 ;//NULL printf("* * * About to exec ls -l\n"... 阅读全文
posted @ 2015-11-29 20:23 20135305 阅读(164) 评论(0) 推荐(0) 编辑