作业信息
| 这个作业属于哪个课程 | <班级的链接>（如2022-2023-1-计算机基础与程序设计） |
|---|---|
| 这个作业要求在哪里 | <作业要求的链接>(如2022-2023-1计算机基础与程序设计第十五周作业) |
| 这个作业的目标 | <> |
| 作业正文 | ... 本博客链接 |
| 要求 | |
| ·课程总结：这个总结写的好的会被选出来出成一本博客书，大家认真写一下，被选中的会送你一本。 | |
| ·文中的链接都要配上二维码，可以使用QQ中的工具或博客园的功能，点击自己每篇文章的最下面的微信图标就有二维码： |
教材学习内容总结
梳理一下第十三章文件操作的一些函数
就当作复习一下吧
| 函数名 | 用法/原型 | |
|---|---|---|
| 函数fopen() | 用来打开文件 | FILE *fopen(const char *filename,const char *mode) |
| 函数fclose() | 用来关闭有fopen打开的文件 | int fclose(FILE *fp) |
| 函数fgetc() | 用于一个只读或读写方式打开的文件上读字符 | int fgetc(FILE *fp) |
| 函数 fputc() | 用于将一个字符写到一个文件上 | |
| 函数 feof() | 检查是否到达文件末尾 | |
| 函数 isprint() | 判断是否为可打印字符 | |
| 其余见图 | ||
 |
||
 |
其他常用函数
pow
字符串处理函数
calloc等
其他（感悟、思考等，可选）
上次小测验遇到一个将字符“1”“2”“3”转成数字123并且改用八进制的题没做对，其中涉及了《C语言程序设计》教材后附录的一些函数的使用
比如pow用来转化进制
可见附录的函数虽然没有强调但是也很重要。因此要认真对待。
实验六
点击查看代码
#include<string.h>
#define N 40
typedef struct student
{
long studentID;
char studentName[10];
int score[3];
float ave;
} STUDENT;
int menu();
void input(STUDENT stu[],int n,int m);
void calc(STUDENT stu[],int n,int m);
void sortascending(STUDENT stu[],int n);
void sortname(STUDENT stu[],int n);
int search(STUDENT stu[],int n);
void prints(STUDENT stu[],int i);
void writetofile(STUDENT stu[],int n);
int readfrom(STUDENT stu[]);
void printScore(STUDENT stu[],int n,int m);
int main()
{
int i;
char select;
STUDENT stu[N];
int n;
printf("How many students?\n");
scanf("%d",&n);
while(1)
{
select=menu();
switch(select)
{
case 1:
input(stu,n,3);
break;
case 2:
calc(stu,n,3);
printScore(stu,n,3);
break;
case 3:
sortascending(stu,n);
printScore(stu,n,3);
break;
case 4:
sortname(stu,n);
printScore(stu,n,3);
break;
case 5:
calc(stu,n,3);
i=search(stu,n);
prints(stu,i);
break;
case 6:
writetofile(stu,n);
break;
case 7:
n=readfrom(stu);
printScore(stu,n,3);
break;
case 0:
printf("End");
exit(0);
default:
printf("Error!");
}
}
}
int menu()
{
int select;
printf("\n1.Append record\n");
printf("2.Caculate total and average score of every student\n");
printf("3.Sort in ascending order by total score of every student\n");
printf("4.Sort in dictionary order by name\n");
printf("5.Search by name\n");
printf("6.Write to a file\n");
printf("7.Read from a file\n");
printf("0.Exit\n");
printf("Please Input your choice:\n");
scanf("%d",&select);
return select;
}
void input(STUDENT stu[],int n,int m)
{
int a,b;
for(a=0; a<n; a++)
{
printf("Input record %d:\n",a+1);
scanf("%ld",&stu[a].studentID);
scanf("%s",stu[a].studentName);
for(b=0; b<m; b++)
{
scanf("%d",&stu[a].score[b]);
}
}
}
void calc(STUDENT stu[],int n,int m)
{
int i,j,sum;
for(i=0;i<n;i++)
{
sum=0;
for(j=0;j<m;j++)
{
sum+=stu[i].score[j];
}
stu[i].ave=(float)sum/m;
}
}
void sortascending(STUDENT stu[],int n)
{
int i,j,k,z,y;
long x;
float m;
char temp[10];
for(i=0;i<n-1;i++)
{
for(j=i+1;j<n;j++)
{
if(stu[i].ave>stu[j].ave)
{
strcpy(temp,stu[i].studentName);
strcpy(stu[i].studentName,stu[j].studentName);
strcpy(stu[j].studentName,temp);
x=stu[i].studentID;
stu[i].studentID=stu[j].studentID;
stu[j].studentID=x;
m=stu[i].ave;
stu[i].ave=stu[j].ave;
stu[j].ave=m;
for(k=0;k<3;k++)
{
y=stu[i].score[k];
stu[i].score[k]=stu[j].score[k];
stu[j].score[k]=y;
}
}
}
}
}
void sortname(STUDENT stu[],int n)
{
int i,j,k,y;
long x;
float m;
char temp[10];
for(i=0;i<n-1;i++)
{
for(j=i+1;j<n;j++)
{
if(strcmp(stu[j].studentName,stu[i].studentName)<0)
{
strcpy(temp,stu[i].studentName);
strcpy(stu[i].studentName,stu[j].studentName);
strcpy(stu[j].studentName,temp);
x=stu[i].studentID;
stu[i].studentID=stu[j].studentID;
stu[j].studentID=x;
for(k=0;k<3;k++)
{
y=stu[i].score[k];
stu[i].score[k]=stu[j].score[k];
stu[j].score[k]=y;
}
m=stu[i].ave;
stu[i].ave=stu[j].ave;
stu[j].ave=m;
}
}
}
}
int search(STUDENT stu[],int n)
{
int i;
char x[10];
scanf("%s",&x);
for(i=0;i<n;i++)
{
if(stu[i].studentName==x) return i+1;
}
}
void prints(STUDENT stu[],int i)
{
int j;
printf("%d\t%10ld",i,stu[i-1].studentID);
for(j=0;j<3;j++)
{
printf("%4d",stu[i-1].score[j]);
}
float x=3*stu[i-1].ave;
printf("%6.1f\t%6.1f\n",x,stu[i-1].ave);
}
void writetofile(STUDENT stu[],int n)
{
FILE *fp;
if((fp=fopen("score.txt","w"))==NULL)
{
printf("Failure to open score.txt!\n");
exit(0);
}
fwrite(stu,sizeof(STUDENT),n,fp);
fclose(fp);
}
int readfrom(STUDENT stu[])
{
FILE *fp;
int i;
if((fp=fopen("score.txt","r"))==NULL)
{
printf("Failure to open score.txt!\n");
exit(0);
}
for(i=0;!feof(fp);i++)
{
fread(&stu[i],sizeof(STUDENT),1,fp);
}
fclose(fp);
printf("Total students is %d.\n",i-1);
return i-1;
}
void printScore(STUDENT stu[],int n,int m)
{
int i,j;
for(i=0;i<n;i++)
{
printf("%d%10ld%8s",i+1,stu[i].studentID,
stu[i].studentName);
for(j=0;j<m;j++)
{
printf("%4d",stu[i].score[j]);
}
printf("%6.1f\t%6.1f\n",3*stu[i].ave,stu[i].ave);
}
}
运行结果
点击查看代码
[root@ecs-20221417 ~]# ls
a.out expersix.c main.c project.two score.txt test
[root@ecs-20221417 ~]# gcc -mabi=lp64 -march=armv8-a -o exper expersix.c -g
[root@ecs-20221417 ~]# ls
a.out exper expersix.c main.c project.two score.txt test
[root@ecs-20221417 ~]# ./test
-bash: ./test: Is a directory
[root@ecs-20221417 ~]# ./exper
How many students?
4
1.Append record
2.Caculate total and average score of every student
3.Sort in ascending order by total score of every student
4.Sort in dictionary order by name
5.Search by name
6.Write to a file
7.Read from a file
0.Exit
Please Input your choice:
1
Input record 1:
20221401 汪汪 85 90 95
Input record 2:
20221403 卷卷 90 95 86
Input record 3:
20221407 瑶瑶 97 98 90
Input record 4:
20221414 露露 90 95 83
1.Append record
2.Caculate total and average score of every student
3.Sort in ascending order by total score of every student
4.Sort in dictionary order by name
5.Search by name
6.Write to a file
7.Read from a file
0.Exit
Please Input your choice:
2
1 20221401 汪汪 85 90 95 270.0 90.0
2 20221403 卷卷 90 95 86 271.0 90.3
3 20221407 瑶瑶 97 98 90 285.0 95.0
4 20221414 露露 90 95 83 268.0 89.3
1.Append record
2.Caculate total and average score of every student
3.Sort in ascending order by total score of every student
4.Sort in dictionary order by name
5.Search by name
6.Write to a file
7.Read from a file
0.Exit
Please Input your choice:
3
1 20221414 露露 90 95 83 268.0 89.3
2 20221401 汪汪 85 90 95 270.0 90.0
3 20221403 卷卷 90 95 86 271.0 90.3
4 20221407 瑶瑶 97 98 90 285.0 95.0
1.Append record
2.Caculate total and average score of every student
3.Sort in ascending order by total score of every student
4.Sort in dictionary order by name
5.Search by name
6.Write to a file
7.Read from a file
0.Exit
Please Input your choice:
4
1 20221403 卷卷 90 95 86 271.0 90.3
2 20221401 汪汪 85 90 95 270.0 90.0
3 20221407 瑶瑶 97 98 90 285.0 95.0
4 20221414 露露 90 95 83 268.0 89.3
1.Append record
2.Caculate total and average score of every student
3.Sort in ascending order by total score of every student
4.Sort in dictionary order by name
5.Search by name
6.Write to a file
7.Read from a file
0.Exit
Please Input your choice:
5
露露
4 20221414 90 95 83 268.0 89.3
1.Append record
2.Caculate total and average score of every student
3.Sort in ascending order by total score of every student
4.Sort in dictionary order by name
5.Search by name
6.Write to a file
7.Read from a file
0.Exit
Please Input your choice:
6
1.Append record
2.Caculate total and average score of every student
3.Sort in ascending order by total score of every student
4.Sort in dictionary order by name
5.Search by name
6.Write to a file
7.Read from a file
0.Exit
Please Input your choice:
7
Total students is 4.
1 20221403 卷卷 90 95 86 271.0 90.3
2 20221401 汪汪 85 90 95 270.0 90.0
3 20221407 瑶瑶 97 98 90 285.0 95.0
4 20221414 露露 90 95 83 268.0 89.3
1.Append record
2.Caculate total and average score of every student
3.Sort in ascending order by total score of every student
4.Sort in dictionary order by name
5.Search by name
6.Write to a file
7.Read from a file
0.Exit
Please Input your choice:
0
学习进度条
| 代码行数（新增/累积） | 博客量（新增/累积） | 学习时间（新增/累积） | 重要成长 | |
|---|---|---|---|---|
| 目标 | 5000行 | 30篇 | 400小时 | |
| 第十四周 | 250/3550 | 2/30 | 24/295 | |
| 第十五周周 | 3500 | 2/4 | 18/38 |
